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Hello guys, I hope I'm in the right section for these kind of problems. I have trouble linking the HTML document with the CSS. I know it's a very dumb problem, and I'm not even a newbie. It's super frustrating because I can't figure out the issue. The document I'm using is for a tutorial about Bootstrap. I downloaded the whole package from the link given by the person making the tutorial - even though the link to the CSS was already given when I opened up the HTML, nothing I write in the CSS has an effect on it. I tried everything - I looked up other people having the same problem, I changed the link several times, I changed the position of the link in the head several times (just to make sure I tried out absolutely everything) without success, I even changed from the MAC I'm working on to a Windows laptop, but nothing works. I created a new HTML and CSS on both MAC and Windows and connected them, they work just fine, so I can't be that dumb - at least I hope so. Can you guys help me? Has it maybe something to do with Bootstrap?

Hi guys! I have a little problem and it's that I get an error in a determined function where I call my connection and I don't know why. The errors are: 1) Notice: Undefined variable: conexionidiomas in C:\wamp64\www\idiomas\preguntas-frecuentes.php on line 10 2) Warning: mysqli_real_escape_string() expects parameter 1 to be mysqli, null given in C:\wamp64\www\idiomas\preguntas-frecuentes.php on line 11 This is what I have from "/Connections/conexionidiomas.php": # FileName="Connection_php_mysql.htm" # Type="MYSQL" # HTTP="true" $hostname_conexionidiomas = "p:localhost:3307"; $database_conexionidiomas = "idiomasbd"; $username_conexionidiomas = "root"; $password_conexionidiomas = "asdasdf"; $conexionidiomas = mysqli_connect($hostname_conexionidiomas, $username_conexionidiomas, $password_conexionidiomas, $database_conexionidiomas); and this in "preguntas-frecuentes.php": <?php require_once('Connections/conexionidiomas.php'); ?> <?php if (!function_exists("GetSQLValueString")) { function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { if (PHP_VERSION < 6) { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; } $theValue = function_exists("mysqli_real_escape_string") ? mysqli_real_escape_string($conexionidiomas, $theValue) : mysqli_escape_string($conexionidiomas,$theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? doubleval($theValue) : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } } $editFormAction = $_SERVER['PHP_SELF']; if (isset($_SERVER['QUERY_STRING'])) { $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']); } if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "form1")) { $insertSQL = sprintf("INSERT INTO tblfrecuentes (strPregunta,fchFecha) VALUES (%s,NOW())",GetSQLValueString($_POST['strPregunta'], "text")); $Result1 = mysqli_query($conexionidiomas,$insertSQL) or die(mysqli_error($conexionidiomas)); } ?> So, if someone could help me I'd appreciate it so much. Regards!

This is my situation If variable $conn has all variables (with a value) $conn = new mysqli($servername, $username, $password, $dbname); and then you use var_dump($conn); and the output would be null of all the values of $conn. What would it mean? Am I right the connection then needs to be re-established? I'm doing 2 queries on a database. First query is SHOW TABLES then make the user choose a table value. From this value a new query is done. So first connection is done. But can I use this connection or should I make a new one?