Jump to content

Search the Community

Showing results for tags 'database'.

  • Search By Tags

    Type tags separated by commas.
  • Search By Author

Content Type


Forums

  • W3Schools
    • General
    • Suggestions
    • Critiques
  • HTML Forums
    • HTML/XHTML
    • CSS
  • Browser Scripting
    • JavaScript
    • VBScript
  • Server Scripting
    • Web Servers
    • Version Control
    • SQL
    • ASP
    • PHP
    • .NET
    • ColdFusion
    • Java/JSP/J2EE
    • CGI
  • XML Forums
    • XML
    • XSLT/XSL-FO
    • Schema
    • Web Services
  • Multimedia
    • Multimedia
    • FLASH

Calendars

  • Community Calendar

Find results in...

Find results that contain...


Date Created

  • Start

    End


Last Updated

  • Start

    End


Filter by number of...

Joined

  • Start

    End


Group


AIM


MSN


Website URL


ICQ


Yahoo


Jabber


Skype


Location


Interests


Languages

  1. Hey guys, i've got a webpage which is password safe by htaccess, but i want to change a few things and i'd like to hear your opinions of how i should execute it at the end. What i've got is: you enter the webpage then you have 1 account to login with via htaccess and then you're on the webpage. What i want is: Something more safe than htaccess. That i can add more users with where i can see when they were last online etc. And idk if htaccess is bruteforce safe but i also need that. My plan was to create a landing page with a login mask connected to an sql database, where all the accounts are managed. Plus the landing page will be with google recaptcha or something like that. What i need to know is, is this the best way to handle all this or do you guys recommend something else? Much appreciated Greetings, Merdo
  2. It would be nice if we also have a tutorial on how to setup and use MongoDB.
  3. There is a table, named student_mark and I have to find which 2 students are having min marks.I also tried group by but it is not working.
  4. Hi everyone, i am using mysql for database and when i am trying to run the query SELECT * FROM carshopdatabase i got the following error message: SELECT * FROM carshopdatabase LIMIT 0, 25 So, why is this happening and how do i fix it? Thanks!
  5. CAN ANYONE HELP? I just upgraded Joomla to the newest version. When I tried to login to the admin i cannot get to anything except this error message: Error: Unknown column 'a.client_id' in 'where clause': Unknown column 'a.client_id' in 'where clause' Can anyone tell me where to start to fix this? Thanks
  6. I want to create a customized birthday greeting for my members once they log in. Requirements: If they log in +/- 7 days from their birthday, show custom greeting in a pop up box only once. - so if they log in every day they only see the greeting once... Show the greeting on their birthday (again or new custom message) if they log in ON their birthday. If they don't log in on their birthday or the +/- 7 days, show a Sorry we missed you, birthday greeting the next time they log in. I can handle the logic part of this, i.e. BDate +/- 7, etc. I just don't know how to keep track of the log ins. I tried searching on the web but I kept getting results specific to development platforms, like WordPress or Wix. I want to write my own code. I assume it should be handled with a counter? on the log in. Or do I create a new line in the membership table for this log in? Can someone point me to some documentation or an example? I don't mind researching it.
  7. Ok, not sure if this is the right forum or not so please point me in the right direction if it's not. Before I dig into the how, I want to know if it's possible to have users request a link through an email link and .. 1) if their email is an approved users they get an email with the link 2) if their email is NOT approved they get a "sorry, you need to be authenticated" message I have a DB of approved emails already on the server. Would it be easier to have the sorry message be an email or can I create a modal that pops up? Also, if they get the sorry message, pretty sure it's possible to send an email back to me indicating an unauthorized request was made, right?
  8. Hi I would like to know how to fetch all columns from a table. Not the data in the table, but only the names of the columns. I made a script. I tested the query first in the console giving me a good result in the section Field . Can someone please explain how to use this in PHP ? code example: <?php // test set up for fetching column names $servername = "localhost"; $username = "name"; $password = "pass123"; $dbname = "test_database"; // $conn = new mysqli($servername, $username, $password, $dbname); if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } if ($stmt = $conn->prepare("SHOW COLUMNS FROM test_table ")) { $stmt->execute(); $row = $stmt->fetch(); var_dump($stmt); var_dump($row); foreach ($row as $value) { var_dump($value); } } $stmt->close(); $conn->close(); ?> EDIT: I solved the script in the following way. <?php $stmt = $conn->prepare("SHOW COLUMNS FROM test_table"); $stmt->execute(); $res = $stmt->get_result(); var_dump($res); foreach ($res as $val){ $col = $val['Field']; var_dump($col); } ?> You have to remove the if part and the {} and replace it with the code above.
  9. Hello, I'm a newbie developer and I'm just wondering if these forums would be an appropriate place to post the designs for a database I'm working on? I'm working on a site that people can use to keep track of their game collection. It's the first database I've designed entirely by myself and I'm looking for a place to post it so I can get some feedback on it. I see there's a thread for posting finished sites, is there a similar thread for databases? Thanks, Jay
  10. Hello, I have a question about how to send form data to the database, without reloading the entire page. I discovered working with xmlhttprequest. I managed to show text from another file by implementing a javascript function with xhr into my script. I don’t know much about javascript and don’t understand how a javascript form should be added to an existing function. Finally this should run a php script executing the code to add the form data to the database. <!DOCTYPE html> <html> <body bgcolor="grey"> <center> <br><br><br> <div style="height: 200px; width: 600px; border: solid 2px blue;"> <div id="kn_ze"> <form id="my_form" action=""> Give your name: <input type="text" name="fname"> <br> <input type="submit" value="Send" onclick="loadXMLDoc();"> <!-- <button type="button" onclick="loadXMLDoc()">send it</button> --> </form> </div> </div> <script> function loadXMLDoc() { /* document.getElementById("my_form").submit();*/ var xhttp = new XMLHttpRequest(); xhttp.onreadystatechange = function() { if (this.readyState == 4 && this.status == 200) { document.getElementById("kn_ze").innerHTML = this.responseText; } }; xhttp.open("GET", "prophp.php", true); xhttp.send(); } </script> </body> </html> test script to process the form data prophp.php : <?php echo '<br>test code here : '; if (isset($_POST['fname'])) { var_dump($_POST['fname']); // execute mysql queries } ?> 11) How are the form data placed in the existing function? (or should I create a second one? ) Maybe someone can help me out solving it.
  11. First off, thanks for letting me into the forums. Excuse a newbie but I have a question about fetching data from a database with PHP and AJAX. Let's say I wanted to fetch data from the database like in this example from W3Schools, but I had modified the dropdown to for example fetch all entries with last name Griffin, Swanson or Quagmire. I made the q variable take a string instead of an integer. $q = strval($_GET['q']); Now I want to expand the SQL query to also take another condition. "SELECT * FROM user WHERE LastName = '".$q."' AND Hometown = '".$q2."'"; I understand how to build the query and that I need to declare another variable (q2), but how do I modify the AJAX request? xmlhttp.open("GET","getuser.php?q="+str,true); Also, would I need to have a submit button now that there are two conditions? Thanks!
  12. I was wondering if there is any way to set unique values to each cookie. I want to use these cookies on my website to see if the visitor has already visited my website once, but without asking any information from them. This way I want to store this unique value in my database each time someone opens my website, and I will be able to see if there have been - for example - 20 different visitors in the past month, or if the same person has visited my website 20 times. All my code is already written and working, I only need a way to set a different unique value to each cookie I set.
  13. Hi all, I'm trying to create a query which selects fields from 2 tables. I have a table 'stock' to store cars for sale and a table called 'custstock' which has the customer username and the vehID. How do I show all the cars that relate the that user who is logged in? My current query that doesn't work; $username = "-1"; if(isset($_SESSION['username'])){ $username = $_SESSION['username']; } // executeable query $sql = ("SELECT * FROM [stock] JOIN custstock ON [stock].custstockvehID = custstock.vehID WHERE username = '$username'"); Thanks, Jack
  14. Desperately needed: a way to retrieve all records from a database table while using prepared statements. The script now works but only for 1 record. <?php $_POST['id']= '2'; // set connection variables // Create connection $conn = new mysqli($servername, $username, $password, $dbname); // Check connection if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } $stmt = $conn->prepare("SELECT * FROM table WHERE id LIKE ? ;"); if ( !$stmt ) { yourErrorHandler($conn->error); // or $mysqli->error_list } else if ( !$stmt->bind_param('i', $id ) ) { yourErrorHandler($stmt->error); // or $stmt->error_list } else if ( !$stmt->execute() ) { yourErrorHandler($stmt->error); // or $stmt->error_list } else { $result = $stmt->get_result(); while ($row = mysqli_fetch_assoc($result)) { var_dump($row); $data[]=$row; var_dump($id); var_dump($data); $array= implode("|" , $row) ; var_dump($array); foreach( $data as $row ) { $id = $row['id']; $name = $row['name']; var_dump($id); var_dump($name); } } } ?> I hope someone can give a query that executes what is desired, but maybe there is also a possibilty to put the query in a loop? Please help.
  15. Hi I am having trouble inserting data into my MySQL database. This is my PHP code ini_set('display_errors', 1); ini_set('display_startup_errors', 1); error_reporting(E_ALL); static $connection; if(!isset($connection)) { $connection = new mysqli("localhost","username","password"); } if ($connection->connect_error) { die("Connection failed: " . $connection->connect_error); } $stmt = $connection->prepare("INSERT into Product(product_title,product_price,product_availability,productImage_1,productImage_2,productImage_3,productImage_4,product_description,product_shipping,product_pickup) VALUES(?,?,?,?,?,?,?,?,?,?)"); $product_title = $_POST['title']; $product_price = $_POST['price']; $product_availability = $_POST['stock']; $null = NULL; $product_description = $_POST['description']; $product_shipping = $_POST['postage']; $product_pickup = $_POST['pickup']; $stmt->bind_param('sisbbbbsis',$product_title,$product_price,$product_availability,$null,$null,$null,$null,$product_description,$product_shipping,$product_pickup); $stmt->send_long_data(3, file_get_contents($_FILES['img1']['tmp_name'])); $stmt->send_long_data(4, file_get_contents($_FILES['img2']['tmp_name'])); $stmt->send_long_data(5, file_get_contents($_FILES['img3']['tmp_name'])); $stmt->send_long_data(6, file_get_contents($_FILES['img4']['tmp_name'])); $stmt->execute(); $stmt->close(); $connection->close(); echo "Product inserted successfully"; I am also getting these errors. Notice: Undefined index: title in /Applications/MAMP/htdocs/Bourke/insertproduct.php on line 61 Notice: Undefined index: price in /Applications/MAMP/htdocs/Bourke/insertproduct.php on line 62 Notice: Undefined index: stock in /Applications/MAMP/htdocs/Bourke/insertproduct.php on line 63 Notice: Undefined index: description in /Applications/MAMP/htdocs/Bourke/insertproduct.php on line 67 Notice: Undefined index: postage in /Applications/MAMP/htdocs/Bourke/insertproduct.php on line 68 Notice: Undefined index: pickup in /Applications/MAMP/htdocs/Bourke/insertproduct.php on line 69 Fatal error: Call to a member function bind_param() on boolean in /Applications/MAMP/htdocs/Bourke/insertproduct.php on line 71 Thanks in advance.
  16. <?php $host = 'localhost'; $username = 'root'; $password = ''; $datadase = 'registerfinal'; $connect = mysqli_connect($host, $username, $password) or die ('error to connect to datadase'.mysqli_error()); if ($connect) { echo 'mysqli connect succsessfull'; } echo '<br /><br />'; $selectdb = mysqli_select_db($connect, $datadase) or die ('unable to select datadase'.mysqli_error()); if($selectdb) { echo 'database selected succsessfully'; } if(isset($_POST['savedetails'])) { $firstname = $_POST['firstname']; $lastname = $_POST['lastname']; $username = $_POST['username']; $password = $_POST['password']; $repeat_password = $_POST['repeat_password']; $gender = $_POST['gender']; $country = $_POST['country']; if(isset($_POST['food'])) { $food = $_POST['food']; $favfood = ""; foreach($food as $meal ) { $favfood = $meal.","; print_r($favfood); } } if(isset($_POST['imageUpload'])) { $imageUploadname = $_FILES['imageUpload']['name']; $imageUploadsize = $_FILES['imageUpload']['size']; $imageUploadtmp_name = $_FILES['imageUpload']['tmp_name']; $imageUploadtype = $_FILES['imageUpload']['type']; $uploadFolder = "uploadFolder/"; $destinationName = rand(1000, 10000).$imageUploadname; move_uploaded_file($imageUploadtmp_name, $uploadFolder.$destinationName); echo "$imageUploadname"; echo "$imageUploadsize"; echo "$imageUploadtmp_name"; echo "$imageUploadtype"; echo "$destinationName"; } $sqltwo = "INSERT INTO `registerfinaltable` (`id`, `firstname`, `lastname`, `username`, `password`, `repeat_password`, `gender`, `food`, `country`, `imageUploadname`, `imageUploadsize`, `imageUploadtype`) VALUES (NULL, '$firstname', '$lastname', '$username', '$password', '$repeat_password', '$gender', '$favfood', '$country', '$destinationName', '$imageUploadsize', '$imageUploadtype')"; $results = mysqli_query($connect, $sqltwo) ; if($results){ echo "inserted successfully"; } } ?> <html> <head> <title>register</title> </head> <body> <form action = "" method = "post" enctype = "multipart/form-data" > <label>first name : <input type = "text" name = "firstname" /> </label> <br /><br /> <label>last name : <input type = "text" name = "lastname" /> </label><br /><br /> <label>username : <input type = "text" name = "username" /> </label><br /><br /> <label>password : <input type = "password" name = "password" /> </label><br /><br /> <label>repeat password : <input type = "password" name = "repeat_password" /> </label><br /><br /> <label>Male : <input type = "radio" name = "gender" value = "Male" /> </label><br /><br /> <label>Female : <input type = "radio" name = "gender" value = "Female" /> </label><br /><br /> <label>pizza : <input type = "checkbox" name = "food[]" value = "pizza"/> </label><br /><br /> <label>burger : <input type = "checkbox" name = "food[]" value = "burger"/> </label><br /><br /> <label>chips : <input type = "checkbox" name = "food[]" value = "chips"/> </label><br /><br /> <label>sausage : <input type = "checkbox" name = "food[]" value = "sausage"/> </label><br /><br /> <label>sandwich : <input type = "checkbox" name = "food[]" value = "sandwich"/> </label><br /><br /> <label>Image : <input type = "file" name = "imageUpload" /> </label><br /><br /> <select name = "country"> <?php $sql = 'SELECT * FROM `countrie` '; $querry = mysqli_query($connect, $sql); while($country = mysqli_fetch_array($querry)):; ?> <option value = "<?php echo $country['country']; ?>"><?php echo $country['country']; ?></option> <?php endwhile;?> </select> <br /> <input type = "submit" name = "savedetails" /> </form> <table border = "1" bgcolor = "" width = "100%"> <tr><th>id</th><th>Firstname</th><th>Lastname</th><th>Username</th><th>Password</th><th>Password 2</th><th>Gender</th><th>Fav. Food</th> <th>Image</th> <th>Country</th><th>imageUploadname</th><th>imageUploadsize</th><th>imageUploadtype</th></tr> <?php $sqldata = "SELECT * FROM registerfinaltable"; $querysqldata = mysqli_query($connect, $sqldata); while($rows = mysqli_fetch_array($querysqldata) ):; ?> <tr> <td><?php echo $rows['id'];?></td> <td><?php echo $rows['firstname'];?></td> <td><?php echo $rows['lastname'];?></td> <td><?php echo $rows['username'];?></td> <td><?php echo $rows['password'];?></td> <td><?php echo $rows['repeat_password'];?></td> <td><?php echo $rows['lastname'];?></td> <td><?php echo $rows['gender'];?></td> <td><?php echo $rows['food'];?></td> <td><?php echo $rows['country'];?></td> <td><?php echo $rows['imageUploadname'];?></td> <td><?php echo $rows['imageUploadsize'];?></td> <td><?php echo $rows['imageUploadtype'];?></td> <?php endwhile;?> </tr> </table> </body> </html>
  17. My goal is to store javascript code into a database. My first idea was to use htmlspecialchars; store it in mysql in a table column and later retrieve it with htmlspecialchars_decode. All this to prevent injection / hacking. But online I read one or two warnings that it wouldnt work, which I assume is so (I didnt test it, but it seems quite obvious afterwards) . So my question is: is it possible to have a user store javascript in a database and use it in a php script for specific purposes in a secure way?
  18. What is BMC remedy database? How to fetch data from this DB to display as XML files. Please provide any links ?
  19. Hi, I'm currently experiencing difficulties updating the database. I'm currently creating a 'Forgotten Password' feature. I've finished most of it, however when I attempt to update the database with a new password, nothing happens and the old password remains in the database. I've followed W3Schools example but I'm stuck. --------- The new password is generated by numbers 4 in total, ie $new_pass = (rand(1000,9999); and from the form I've used $user_email= $_POST["retrieve_email"]; then I use the line sql = "UPDATE registration SET Password=$new_pass WHERE Email=$user_email"; I can't get it to work, and I don't know why. Could anyone please write the code I need to make it work, or let me know how to proceed? Thank You. ps. I thought about deleting the entry and re-inserting it. Would that work (out of interest)?
  20. I have a piece of code where I use MYSQL to add records into a database. Here I use INSERT, but I want to work with UPDATE. The user selects records which have to be updated. The records have a unique number. I hope people can help me how to convert MYSQL code into PHP. The MYSQL code used in the console is this: UPDATE table_name SET input2='my input here ' WHERE rec_number = 2; The part of the script I use looks like this: <?php $name1 = $conn->real_escape_string($input1); $name2 = $conn->real_escape_string($input2); // $sql = "INSERT INTO $table (input1, input2 ) VALUES (' $name1 ', ' $name2 ')" ; // olde code // $sql = "UPDATE $table SET input2, input1 WHERE rec_number = $rec_number_selected VALUES (' $name1 ', ' $name2 ')" ; $sql = "UPDATE $table (input1, input2) VALUE S (' $name1 ', ' $name2 ') WHERE rec_number = $rec_number_selected " ; ?> Anyone any idea what the right code is in PHP?
  21. So recently I got my hands on one of youtube videos, it's quit old, and the guy explaining how to create a form for uploading image and all data that is connected with it, to MySQL and then showing on your web site. So everything is ok, but webpage does not display any images, it just show me white picture frame with picture icon on the top. This is my connection file with database: <?php $hostname_phpimage = "***"; $username_phpimage = "***"; $password_phpimage = "***"; $database_phpimage = "***"; // Create connection $inkedmen_marko = mysql_pconnect($hostname_phpimage, $username_phpimage, $password_phpimage); // Check connection if ($phpimage->connect_error) { die("Connection failed: " . $phpimage->connect_error); } ?> Then the file that uploads the images: <?php require_once('php/connect.php'); if($_POST['submit']) { $name=basename($_FILES['file_upload']['name']); $t_name=$_FILES['file_upload']['tmp_name']; $dir='/home4/inkedmen/public_html/images'; $cat=$_POST['cat']; if(move_uploaded_file($t_name,$dir."/".$name)) { mysql_select_db($database_phpimage, $inkedmen_marko); $qur="insert into anglija (mid, cid, name, path) values ('','$cat','$name','/home4/inkedmen/public_html/images/$name')"; $res=mysql_query($qur,$inkedmen_marko); echo'file upl success'; } else { echo 'not uploaded'; } } ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> </head> <body> <form action="upload.php" method="post" enctype="multipart/form-data"> <input type="file" name="file_upload"/> cat_id <input type="text" name="cat" /><br/> <input type="submit" name="submit" value="upload"/> </form> </body> </html> Then this one shows me what countries I have in one of the data base tables, so there is two england and slovenia, they both have a separate id that I have to type when uploading an image: <?php require_once('php/connect.php'); mysql_select_db($database_phpimage, $inkedmen_marko); $qur="select * from cat"; $res=mysql_query($qur,$inkedmen_marko); ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> </head> <body> <?php while($row= mysql_fetch_array($res)) { ?> <h1><a href="image.php?cid=<?php echo $row['id']?>"><?php echo $row['name'] ?> </a></h1><br/> <?php } ?> </body> </html> And finally, when I push on each country it directs me to the pictures that are connected with that countries according to the id given: <?php require_once('php/connect.php'); mysql_select_db($database_phpimage, $inkedmen_marko); $id=$_GET['cid']; $qur="select * from anglija where cid='$id'"; $res=mysql_query($qur,$inkedmen_marko); ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> </head> <body> <?php while ($row=mysql_fetch_array($res)){ ?> <img src="<?php echo $row['path'] ?>" width="300px" height="200px"> <br/> <?php } ?> </body> </html> So in the end it directs me to the pictures, but I can't see the pictures, it's just white windows with icon on the top. The pictures uploads to the image folder, the id, names of the file, path also uploads good, but somehow I can't show the images. I know it should be something small, but I can't figure it out. Maybe someone have any ideas????
  22. Hi I'm looking for php/mysql code to find identical input in a mysql database column.
  23. ugintl

    Database error

    I uploaded website files to the web root and when i tried to access it via www.mydomain.com it gave following error A Database Error OccurredError Number: 1146 Table 'webpk_16901224_app.sesion' doesn't exist INSERT INTO `sesion` (`session_id`, `ip_address`, `user_agent`, `last_activity`, `user_data`) VALUES ('1912dd6c2dd5c411cde798d9496c9a9a', '119.157.163.66', 'Mozilla/5.0 (Windows NT 5.1; rv:42.0) Gecko/20100101 Firefox/42.0', 1448544788, '') Filename: libraries/Session.php Line Number: 328 I tried to create a table like following through phpmyadmin, but i get an error "key id does not exist". My database name is webpk_16901224_app and it is empty. There are no tables. create table tablename( id INT NOT NULL, name VARCHAR (20) NOT NULL, age INT NOT NULL, PRIMARY KEY (id) ); The website script has 3 sql files, but i don't know how to use them. SQL files are attached. Desktop.zip
  24. Hello. I'm currently developing an app in the Intel XDK for my local high school. One of the features I would like to add is something where school administrators (such as the athletic director) can login and then submit data into an HTML5 form, which is then submitted to a server and stored in a database. Then, after it is stored, I would like the information to be able to be viewed by regular users of the app, in something such as an HTML page. THe purpose of this would be for the school admins to submit scores from the games such as football, etc. My question is, how do I setup the server (im assuming would run PHP) to be able to store the submitted data, and then would edit an HTML page to include the new text? Any help is appreciated! Thanks!
  25. I am trying to make a result page so I can get some information from the database by using php coding. I need it to be able to find a patient name and date of service. Which will be if I type in (Search:) Joe Doe and add (from:) 02/02/2015 (to:) 02/14/2015. It will find the patient name and all date of service. Here is my code ... I know mysql is not good but it will work for now. <?phpmysql_connect('localhost', 'root', 'no_password');mysql_select_db('timeclock');$results = array();if(isset($_GET['search'])) { $search = $_GET['search_box']; $from = $_GET['from']; // or $from = $_get['from']; $to = $_GET['to']; // or $to = $_get['to']; $sql = mysql_query("SELECT * FROM info WHERE patient_name = '".$search."' AND (date_of_service BETWEEN '".$from."' AND '".$to."')"); while($row = mysql_fetch_assoc($sql)) { $results[] = $row; }}?><!-- form --><form name="search_form" method="GET" action="">Search: <input type="text" name="search_box" value="" />Dates From : <input type="text" name="from" value=""/> To : <input type="text" name="to" value=""/><input type="submit" name="search" value="Look up Patient ..."></form><!-- end --><table width="70%" cellpadding="5" cellspace="5"><tr> <td><strong>Care Provider</strong></td> <td><strong>Patient Name</strong></td> <td><strong>Date of Time</strong></td> <td><strong>Time In</strong></td> <td><strong>Time Out</strong></td> <td><strong>Remarks</strong></td></tr><?php if(!empty($results)): ?><?php foreach($results as $row){ ?><tr> <td><?php echo $row['care_provider']; ?></td> <td><?php echo $row['patient_name']; ?></td> <td><?php echo $row['date_of_service']; ?></td> <td><?php echo $row['time_in']; ?></td> <td><?php echo $row['time_out']; ?></td> <td><?php echo $row['remarks']; ?></td></tr><?php } ?><?php endif; ?></table>
×
×
  • Create New...