How Can We Calculate The Elapsed Time For A Function To Be Executed?

[Eyad Syria-lover]

I Have Just Read About The performance.now() Standard,But I Felt Uncomfortable About It.

Is There Any Other Way To Solve This?.

[Ingolme]

If you care about compatibility with older browsers, you can use Date() objects. It has millisecond precision, but you can benchmark code by running it thousands of times.

var iterations = 100000;

var start = (new Date()).getTime();
for(var i = 0; i < iterations; i++) {
  // Put code here for benchmarking
}
var end = (new Date()).getTime();

// Find out how long it took
var elapsedTime = end - start;

// Find out how much time passes for just one function call
var averageTime =  elapsedTime / iterations;

// Output data
console.log(averageTime);

[justsomeguy]

But I Felt Uncomfortable About It.

What does that mean? What about it makes you feel uncomfortable?

[Eyad Syria-lover]

What does that mean? What about it makes you feel uncomfortable?

It's Returning So Many Numbers After Decimal...

Like This:

 

10.925054550170898

[Eyad Syria-lover]

If you care about compatibility with older browsers, you can use Date() objects. It has millisecond precision, but you can benchmark code by running it thousands of times.

var iterations = 100000;

var start = (new Date()).getTime();
for(var i = 0; i < iterations; i++) {
  // Put code here for benchmarking
}
var end = (new Date()).getTime();

// Find out how long it took
var elapsedTime = end - start;

// Find out how much time passes for just one function call
var averageTime =  elapsedTime / iterations;

// Output data
console.log(averageTime);

This Is Taking More Than Expected Because The Iteration Is Very Big,Do You Have Another Way Sir?

[Ingolme]

Reduce the number of iterations.

[justsomeguy]

It's Returning So Many Numbers After Decimal...

So, what's the problem? Most floating-point numbers in Javascript aren't going to be precise after a few decimals, so if the precision of that is supposed to be to 3 decimal places then you can drop the other digits.