skyhighweb Posted May 25, 2017 Share Posted May 25, 2017 i need to connect team1 and team2 to a table called sports so i can get there names which is in column called (teams) how do i do that i already connected sports to another table as u can see in the code, how do i go about this, thanks. $query = "SELECT s.team_id, s.teams, a.current_bid, a.current_bid_id, a.id, a.team1, a.title, a.team2, a.ends, a.starts, u.nick, b.bid, b.tagged, b.bidder, b.willwin, b.quantity, p.bid As proxybid, b.id As bid_id FROM " . $DBPrefix . "bids b LEFT JOIN " . $DBPrefix . "proxybid p ON (p.itemid = b.auction AND p.userid = b.bidder) LEFT JOIN " . $DBPrefix . "sports s ON (s.team_id = b.willwin) LEFT JOIN " . $DBPrefix . "auctions a ON (a.id = b.auction) LEFT JOIN " . $DBPrefix . "users u ON (u.id = b.tagged) Link to comment Share on other sites More sharing options...
skyhighweb Posted May 25, 2017 Author Share Posted May 25, 2017 ok done did it this way just incase someone wants to know how $query = "SELECT sss.team_id, sss.teams AS teams2, ss.team_id, ss.teams AS teams1, s.team_id, s.teams, a.current_bid, a.current_bid_id, a.id, a.team1, a.title, a.team2, a.ends, a.starts, u.nick, b.bid, b.tagged, b.bidder, b.willwin, b.quantity, p.bid As proxybid, b.id As bid_id FROM " . $DBPrefix . "bids b LEFT JOIN " . $DBPrefix . "proxybid p ON (p.itemid = b.auction AND p.userid = b.bidder) LEFT JOIN " . $DBPrefix . "sports s ON (s.team_id = b.willwin) LEFT JOIN " . $DBPrefix . "auctions a ON (a.id = b.auction) LEFT JOIN " . $DBPrefix . "sports ss ON (ss.team_id = a.team1) LEFT JOIN " . $DBPrefix . "sports sss ON (sss.team_id = a.team2) LEFT JOIN " . $DBPrefix . "users u ON (u.id = b.tagged) Link to comment Share on other sites More sharing options...
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