j.silver Posted October 30, 2014 Share Posted October 30, 2014 Dear all, some help will be highly appreciated. I have a JS code that has a form for first name and last name. Ajax then communicates with a PHP script and gets back a message from PHP that thanks the user by stating the first and last names of user. The PHP message will show at the bottom of the form without having the page to refresh. The PHP message ensures a successful communication between JS and PHP via Ajax. The JS script:<!DOCTYPE html><html lang="en"><head><script>function ajax_post() {//create our XMLHttpRequest objectvar hr = new XMLHttpRequest();//create some variables we need to send to our PHP filevar url = "my_parse_file.php"; //name of the PHP parsing script.var fn = document.getElementById("first_name").value;var ln = document.getElementById("last_name").value;var vars = "firstname="+fn+"&lastname="+ln; //variables to be sent to PHP scritp.hr.open("post", url, true); //using the open method on XMLHttpRequest object.hr.setRequestHeader("Content_type", "application/x-www-form-urlencoded");// access the onreadystatechange event for the XMLHttpRequest object.hr.onreadystatechange = function() {if (hr.readyState == 4 && hr.status == 200) {var return_data = hr.responseText;document.getElementById("status").innerHTML = return_data;}}// send the data to PHPhr.send(vars);document.getElementById("status").innerHTML = "processing...";}</script></head><body><h2>Ajax Post to PHP and Get Return Data</h2>Your First Name: <input id="first_name" name="first_name" type="text" /><br /><br />Your Last Name: <input id="last_name" name="last_name" type="text" /><br /><br /><input name="myBtn" type="submit" value="Submit Data" onClick="javascript:ajax_post();" /><br /><br /><div id="status"></id></script></body></html>The PHP script:<?phpecho 'Thank you ' . $_POST['firstname'] . ' ' . $_POST['lastname'] . ',says the PHP file.';?>I receive no message back from the PHP script as desired, only the word "processing...".As part of the debugging, I inserted:document.write("Ready State = "+hr.readyState + " Ready Status = "+hr.status);after: hr.onreadystatechange = function() {The message I got was: Ready State = 4 Ready Status = 0.I thought it meant changing the 200 to 0, but still didn't work.My system: Apache, PHP 5.5.9, Windows 64-bit OS, Windows 7 Link to comment Share on other sites More sharing options...
niche Posted October 30, 2014 Share Posted October 30, 2014 (edited) compare your script to the script in this tut: http://www.w3schools.com/php/php_ajax_php.asp I see differences in required areas. Edited October 30, 2014 by niche Link to comment Share on other sites More sharing options...
justsomeguy Posted October 30, 2014 Share Posted October 30, 2014 You can use the network tab in your browser's developer tools to see the ajax request go out, and also to check the response. It might not be a 200 response. You can also check for Javascript error messages on the console. Link to comment Share on other sites More sharing options...
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