Jump to content

m2008

Members
  • Posts

    2
  • Joined

  • Last visited

m2008's Achievements

Newbie

Newbie (1/7)

0

Reputation

  1. i am beginner. Who has an example?
  2. I have script a.php <html> <head> <link rel="stylesheet" type="text/css" href="f.css"> </head> <body> <ul> <li><a class="active" href="afisare.php">Home</a></li> <li><a href="#news">News</a></li> <li><a href="#contact">Contact</a></li> <li><a href="#about">About</a></li> </ul> </body> </html> and script afisare.php: <?php session_start(); // conectare la server $conn = new mysqli('localhost', 'root', '', 'db'); // verifica conexiunea if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } //require_once('conectare.php'); echo "<div id=\"continut\">"; $sql = "select denumire,pret,categorie from poze"; $result = $conn->query($sql); $nr=$result->num_rows; for ($i=0;$i<$nr;$i++) { $row=$result->fetch_assoc(); $poza=$row['denumire'].'.jpg'; echo "<img src=\"".$poza."\" style=\"width:200px;height:200px\">"; } echo "</div>"; ?> if click on link Home, i want display result of script afisare.php in page of a.php, in new div element. How do it?
×
×
  • Create New...