phppro Posted June 9, 2013 Share Posted June 9, 2013 how can i create dynamic rss feed using php fo my website....and how can show dynamically that feed please give me proper guideline. Link to comment Share on other sites More sharing options...
niche Posted June 9, 2013 Share Posted June 9, 2013 http://www.w3schools.com/rss/ Link to comment Share on other sites More sharing options...
guruparthi Posted August 20, 2014 Share Posted August 20, 2014 First of all you need to store all urls of your website to mysql database. Then retrieve from db and make RSS feed dynamically using PHP. Example Code is <?phpheader("Content-Type: application/rss+xml; charset=ISO-8859-1");echo '<?xml version="1.0" encoding="UTF-8" ?><?xml-stylesheet type="text/xsl" media="screen" href="/~d/styles/rss2full.xsl"?><?xml-stylesheet type="text/css" media="screen" href="http://feeds.feedburner.com/~d/styles/itemcontent.css"?><rss xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:sy="http://purl.org/rss/1.0/modules/syndication/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:feedburner="http://rssnamespace.org/feedburner/ext/1.0" version="2.0"><channel> <title>Phponwebsites</title> <link>http://www.phponwebsites.com</link> <description>Phponwebsites about php related topics like .htaccess, robots.txt, mysql, jquery, ajax, js and also php for php developers</description>'; $connection = @mysql_connect('localhost', 'root', '') or die(mysql_error()); mysql_select_db('new') or die (mysql_error()); $query = "SELECT * FROM links order by id desc"; $rss = mysql_query($query) or die (mysql_error()); $ImgPath='http://2.bp.blogspot.com/-vwl4cGyoDPM/UqKklyTGE-I/AAAAAAAAALI/iOipE7-PhAM/s1600/logo5.png'; while($row=mysql_fetch_array($rss)){ echo ' <item> <title>'.$row['name'].'</title> <link>'.$row['link'].'</link> <content:encoded> <![CDATA[<p align="left"> <a href="'.$row['link'].'"><img style="background-image: none; " border="0" src="'.$ImgPath.'" /> </a></p>]]> </content:encoded> <description>'.$row['description'].'</description></item>'; } echo '</channel></rss>';?> Link to comment Share on other sites More sharing options...
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