((

[Drycodez]

if((A==1)&&(B==2)){return (true)}

y is extra brackets surrounding the condiction and the true statement?

[jeffman]

None is required. You sometimes see that in conditions when multiple expressions are joined with && or ||, as here, to make it more readable. I see no use in surrounding a return value with (), but maybe some developers find it makes the expression more readable. Maybe it's required in other languages and they do it from force of habit?

[ShadowMage]

The parens in the condition are just a way to group statements. Sometimes, when and expression could be ambiguous, they are required (EDIT: That is, required in order to achieve expected results). Usually, though, it is just a matter of readability.This:if ((A==1)&&(B==2))is easier to read than:if (A==1&&B==2)because it clearly separates each condition that must be checked.As for the parens around true, I don't think there really is a purpose. Developer habit?Though it seems like it should return a boolean object (rather than a plain boolean value), similar to the way that ("a string").substr(2) works...

[Drycodez]

Group?

{document.write('A'); alert('B');}

the curly braces group the above statement 2geda! Does it mean dat ( and ) can do thesame?

[justsomeguy]

Consider this:if (A == 1 && B == 2 || C == 3)You would probably want to explicitly group those so it's obvious whether you mean this:if ((A == 1 && B == 2) || C == 3)or this:if (A == 1 && (B == 2 || C == 3))And no, parentheses are not a replacement for curly brackets.

[thescientist]

Group?

{document.write('A'); alert('B');}

the curly braces group the above statement 2geda! Does it mean dat ( and ) can do thesame?

that would only work in the context of function scope, there's a big difference for why and when the two are used (parens vs. braces). the parenthesis in the original context are just conveniences founded on the simple rules of order of operations; aka PEMDAS - parenthesis, exponents, multiplication, division, addition, subtraction.

[Drycodez]

Thanks i

[ShadowMage]

Consider this:if (A == 1 && B == 2 || C == 3)You would probably want to explicitly group those so it's obvious whether you mean this:if ((A == 1 && B == 2) || C == 3)or this:if (A == 1 && (B == 2 || C == 3))

So I know I've got this right:The order of operations here goes from left to right, correct? So without parens, you would get the same behavior as this:if ((A == 1 && B == 2) || C == 3)Or is it the other way around?

[justsomeguy]

The logical && and || operators do go from left to right, but && has a higher precedence than ||. It will evaluate the && before the ||, regardless of which one is farther left.https://developer.mozilla.org/en/JavaScript...ator_Precedence

[jeffman]

I always test the heck out of complex Booleans. Error console is good for that.

[Drycodez]

afta my experiment, i noticed the () is jux lyk d 1 dat preceed functions name. Its used to group statement (for readerbility) and to pass argument to what it precceed!

[justsomeguy]

I don't think I understood that, perhaps you could write that again using English.