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ak47

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About ak47

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  1. Here my question is how to print/display the numbers from pressed buttons(as shown in figure) using JavaScript. However, here I am working on a device and we have to control it from JavaScript. Below I have mentioned my code(.js) snippet:// Numbers functionfunction Numbers(cmd){System.Print("Command Sent is: "+cmd);var num = cmd;System.Print("Button pressed is: "+num);}// Displaying Numbersfunction Display(){Numbers(num);num.toString();dbgPrint("Displaying number: " + num);}And parameters for this function I am passing from some other file(.xml) as standard.<function name="Display" export="Display"><parameter name="display" type="string" description="Drag and drop this for clear-button function."></parameter></function><function name="Numbers" export="Numbers"><parameter name="command" type="mcinteger" description="Drag and drop this command for Numbers."><choice name="1" value="1"/><choice name="2" value="2"/><choice name="3" value="3"/><choice name="4" value="4"/><choice name="5" value="5"/><choice name="6" value="6"/><choice name="7" value="7"/><choice name="8" value="8"/><choice name="9" value="9"/><choice name="0" value="0"/></parameter></function>
  2. @dsonesuk, I have not completely got your points. It's ok, I will study what you said. Thank you for your valuable time and also for great informations.
  3. Hi all, 1. I want to delete selected(checkbox) items from database(MySQL). Here I am not getting any error, but I couldn't do the delete function.2. Wants to play videos in website. Here videos storing into folder and also into database, but cannot playin website. I tried in many ways, but I couldn't. So, please help to make above mentioned functions workable. dashboard.php<form method="post" enctype="multipart/form-data"><input type="submit" name="delete" class="btn btn-primary" onclick="myFunction(id)" style="font-size: 15px; margin-left: 3em;" value="Delete" /></form><div><?php$query = mysqli_query($database, "SELECT * FROM video");while($row = mysqli_fetch_assoc($query)){$id = $row['id'];$name = $row['name'];$url = "../uploads";// $url = $row['url'];$fileextensionvalue= $row['fileextension'];echo "<span class='col-md-6'><div class='row'><div class='col-md-1'><label class='checkbox'><input style='margin-right:1em;' name='checkbox[<?php echo $id; ?>]' type='checkbox' id='checkbox[]' data-toggle='checkbox' /></label></div><div class='col-md-1'><a href='#' style='color:red;font-size:18px;'>$id</a></div><div class='col-md-10'><a href='#' style='color:red;font-size:18px;'>$name</a></div></div><center style='padding:25px;'><video width='320' preload='auto' controls><source src='$url' type='video/$fileextensionvalue;codecs='avc1.42E01E, mp4a.40.2, H.264, aac, FLAC, Opus, VP9, VP8, Vorbis''/></video></center></span>";}?></div><script type="text/javascript">function myFunction(id){var r=confirm("Are you sure to delete selected video/s ?");if(r==true){window.location.assign("deleteVideo.php?id=" + id);}}</script>deleteVideo.php<?phpinclude '../database/database.php';$sql = mysqli_query($database, "SELECT * FROM video WHERE id='$id'");if(empty($_POST['delete'])){Print '<script>alert("Please choose file/s to delete.");</script>';Print '<script>window.location.assign("dashboard.php");</script>';}else if(!empty($_POST['delete'])){foreach($_POST['checkbox'] as $id => $val){if($val=='checked'){$query=mysqli_query("DELETE FROM video WHERE id = '".$id."'");$result= mysqli_query($database, $query) or die("Invalid query");}}}?>
  4. Thank You @Gabrielphp, Now the videos are not saving upon refreshing the page. I gave URL like this: $url = "http://localhost/xampp/htdocs/VS/uploaded/$name"; and the ip address of my local host is 127.0.0.1. I know the url path is wrong, but I don't know how to make it right. Can you help me please? Here $name is "video name"
  5. Yes, you are right. I know how to use prepare statements but for initiation I used directly. Yes, as you told about "re-submission upon refresh of page" I did that and really it worked for me nicely. I am on the way to make my videos viewable. If I really face problems in future, surely I will contact you. Thank you so much for your valuable investment on my bugs and for your answers and suggestions.
  6. @dsonesuk, I really don't know how to do that. If you don't mind can you help me to fix that by writing the script?
  7. Here I can upload videos successfully into database and videos are saving in appropriate folder named "uploaded". As I mentioned in question, once after uploading the video, if I refresh the browser the previously uploaded video is going saving in my database. Another question is, if I click on the video(displayed name in myvideo.php), video is not going to display instead I am getting "Object Not Found" error. I request you people to give me solutions to solve these problems. Below I am posting my code: myvideo.php: <div class="content"><div class="card"><div class="header" id="stand-fix" style="border-bottom: 1px solid #E1E1E1;"><?phpif(isset($_POST['submit'])){// $conn = mysqli_connect("localhost", "root", "", "videos") or die(mysqli_error());$name = (isset($_FILES['file']['name']) ? $_FILES['file']['name'] : '');$temp = (isset($_FILES['file']['tmp_name']) ? $_FILES['file']['tmp_name'] : '');move_uploaded_file($temp, "uploaded/".$name);$url = "http://localhost/xampp/htdocs/VS/uploaded/$name";mysqli_query($database, "INSERT INTO video VALUE ('','$name','$url')");}?><form action="myvideo.php" method="post" enctype="multipart/form-data"><div class="row"><div class="col-md-7"><h4 class="title">My Videos</h4></div><div class="col-md-3"><input type="file" name="file" class="btn btn-primary" style="font-size: 15px;"><br /></div><div class="col-md-2"><input type="submit" name="submit" class="btn btn-primary pull-right" style="font-size: 15px;" value="Upload"></div></div></form><?phpif(isset($_POST['submit'])){echo '<script language="javascript">';echo 'alert("Your video has been successfully uploaded.")';echo "window.location.href='dashboard.php'";echo '</script>';}?><hr width="50%"></div><div class="content" style="height: 30em; direction: ltr; overflow: auto;"><div class="row" style="margin-left:4em;" style="direction: rtl;"><?php$database = mysqli_connect("localhost", "root", "", "videos") or die(mysqli_error());$query = mysqli_query($database, "SELECT * FROM video");while($row=mysqli_fetch_assoc($query)){$id = $row['id'];$name = $row['name'];$url = $row['url'];echo "<p style='margin:0.5em;'><a href='watch.php?id=$id' style='color:red;'>$id&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;$name</a></p><br />";echo "<embed src='.$id.$url.'><video width='200' height='200' controls></video></embed>";}?></div></div></div></div> watch.php<?php$conn = mysqli_connect("localhost", "root", "", "videos") or die(mysqli_error());if(isset($_GET['id'])){$id = $_GET['id'];$query = mysqli_query($conn, "SELECT * FROM video WHERE id='$id'");while($row=mysqli_fetch_assoc($query)){$name = $row['name'];$url = $row['url'];}echo "<p style='font-size:20px;'><center>You are watching ".$name."</center></p><br /><embed src='.$url.'><video width='600' height='400' controls></video></embed>";}else{echo "Error!";}?>
  8. Hi everyone, thank you for your valuable time you spent on my post. But I didn't wanted to waste your time, so I tried my best. But still I have error "Fatal error: Call to a member function bind_param() on boolean". Kindly give me a solution to get rid-off this. Below is my code: <?php include '../_database/database.php'; ini_set("display_errors",1); session_start(); $msg=""; if($_SERVER["REQUEST_METHOD"] == "POST") { $username = $_POST['Username']; $email = $_POST['Email']; $employee = $_POST['EmployeeID']; $designation = $_POST['Designation']; $password = $_POST['Password']; $id = $_SESSION['Id']; $sql=$database->prepare("UPDATE users SET (Username,Email,EmployeeID,Designation,Password) VALUES (?,?,?,?,?) WHERE Id=?"); $sql->bind_param("ssiss", $username, $email, $employee, $designation, $password); $sql->execute(); if($sql->execute()){ echo "<font face='Verdana' size='2' color='green'>You have successfully updated your profile<br /></font>"; } else{ print_r($sql->errorInfo()); $msg=" <font face='Verdana' size='2' color='red'>There is some problem in updating your profile. Please contact site admin<br /></font>"; } } ?> include '../_database/database.php'; ---- Here I defined database as " $database=mysqli_connect("localhost", "root", "", "videos") or die(mysqli_error());
  9. Sorry, I have made some mistakes in my previous post. And my corrected code is: <?php include '../_database/database.php'; ini_set("display_errors",1); session_start(); $msg=""; $temp=(isset($_SESSION['Username']) ? $_SESSION['Username'] : ''); $id=(isset($_SESSION['Id']) ? $_SESSION['Id'] : ''); if($_SERVER["REQUEST_METHOD"] == "POST") { $username = $_POST['Username']; $email = $_POST['Email']; $employee = $_POST['EmployeeID']; $designation = $_POST['Designation']; $password = $_POST['Password']; $sql=$database->prepare("UPDATE users SET Username=:name,Email=:email,EmployeeID=:employee,Designation=:designation,Password=:password WHERE Id='$id'"); $sql->bindParam(':username',$username,PDO::PARAM_STR, 50); $sql->bindParam(':email',$email,PDO::PARAM_STR, 50); $sql->bindParam(':employee',$employee,PDO::PARAM_INT, 11); $sql->bindParam(':designation',$designation,PDO::PARAM_STR, 50); $sql->bindParam(':password',$password,PDO::PARAM_STR, 50); if($sql->execute()){ echo "<font face='Verdana' size='2' color=green>You have successfully updated your profile<br></font>"; } else{ print_r($sql->errorInfo()); $msg=" <font face='Verdana' size='2' color=red>There is some problem in updating your profile. Please contact site admin<br></font>"; } } ?> But still I have the error: "Fatal error: Uncaught Error: Call to a member function bindParam() on boolean in C:\xampp\htdocs\VS\components\update-profile.php:16 Stack trace: #0 {main} thrown in C:\xampp\htdocs\VS\components\update-profile.php on line 16"
  10. Hi All, I am new to php and I don't about following error. So I request you to give me solution for this and also please explain something about this error. Here I am working on User's profile page. I able to fetch data and displaying in profile's form, but data is not updating and I got the following error when I clicked for "Updation". " Uncaught Error: Call to a member function bindParam() on boolean in C:\xampp\htdocs\VS\components\update-profile.php:16 Stack trace: #0 {main} thrown in C:\xampp\htdocs\VS\components\update-profile.php on line 16 " And my code is: <?php include '../_database/database.php'; ini_set("display_errors",1); session_start(); $msg=""; $temp=(isset($_SESSION['Username']) ? $_SESSION['Username'] : ''); $id=(isset($_SESSION['Id']) ? $_SESSION['Id'] : ''); if($_SERVER["REQUEST_METHOD"] == "POST") { $username = $_POST['Username']; $email = $_POST['Email']; $employee = $_POST['EmployeeID']; $designation = $_POST['Designation']; $password = $_POST['Password']; $sql=$database->prepare("update set Username=:name,Email=:email,EmployeeID=:employee,Designation=:designation,Password=:password where Id='$id'"); $sql->bindParam(':Username',$name,PDO::PARAM_STR, 50); $sql->bindParam(':Email',$email,PDO::PARAM_STR, 50); $sql->bindParam(':EmployeeID',$employee,PDO::PARAM_INT, 11); $sql->bindParam(':Designation',$designation,PDO::PARAM_STR, 50); $sql->bindParam(':Password',$password,PDO::PARAM_STR, 50); if($sql->execute()){ echo "<font face='Verdana' size='2' color=green>You have successfully updated your profile<br></font>"; } else{ print_r($sql->errorInfo()); $msg=" <font face='Verdana' size='2' color=red>There is some problem in updating your profile. Please contact site admin<br></font>"; } } ?> If this is wrong kindly give me a solution. Thank You,
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