kgw

Hi,I post the question to other mailing list and they give me the following xpath/xquery parser. They are W3C recommendation.http://www.w3.org/2005/qt-applets/xpathApplet.htmlhttp://www.w3.org/2005/qt-applets/xqueryApplet.htmlRegards,kgw

Hi boen_robot,Thanks for the article, but actually it's not what I am looking for. I am not looking for XML parser (parser to parse XML document), but rather XPath parser (to parse XPath). But I do not want the XPath parser to evaluate the XPath expression and return me XML nodes (I don't want the XPath parser to query the XML document). Rather, I want the XPath parser to return me an array or a list or tree or anything where I can go step by step. I am looking for something like this:xpath = XPathParser.parse("/a/b[P and Q]/following::*");xpath.step(1) will return axis = child, NameTest = axpath.step(2) will return axis = child, NameTest = b, predicate = P and Qpredicate can further be divided into predicate.part(1) = P, predicate.part(2) = Q, predicate.boolean() = andxpath.step(3) will return axis = following, NameTest = *Thanks,kgw

Hi,Is there any XPath parser written in java?What I want is: given an XPath string, let say /a/b[pred01]/axes::*/... (pred01 can be anything)it would return the steps of the XPath, ex: a, b[pred01], axes, ...or something more detailThanks,kgw

Actually if you want to sort, you can use XQuery - order by

Hi,I've tried to fix some part of your codes but they still throw some errors. Below is the code that I've fixed. You can refer to the comments to see which part I've edited.For your question, you need to give a name to your complexType. <xsd:element name="myResume"><xsd:complexType>... <?xml version="1.0"?><xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <xsd:element name="myResume"> <!--added--> <xsd:complexType> <xsd:sequence> <!--added--> <xsd:element name="category" type="xsd:string"/> <xsd:element name="type" type="xsd:string"/> <xsd:element name="description" type="xsd:string"/> <xsd:element name="accomplishment" type="xsd:string"/> <xsd:element name="class" type="xsd:string"/> <xsd:element name="link" type="xsd:anyURI" /><!--xsd:urireference"/>--> <xsd:element name="role" type="xsd:string"/> <xsd:element name="Date" type="xsd:string"/> <xsd:element name="status"> <!-- type="statusType">--> <!--comment--> <xsd:simpleType> <!--added--> <xsd:restriction base="xsd:string"> <xsd:enumeration value="Development"/> <xsd:enumeration value="In Progress"/> <xsd:enumeration value="Complete"/> <xsd:enumeration value="Ongoing"/> </xsd:restriction> </xsd:simpleType> </xsd:element> <xsd:element name="skill"> <xsd:complexType> <xsd:sequence> <xsd:element ref="xsd:name"/> <xsd:element ref="xsd:category"/> <xsd:element ref="xsd:link"/> </xsd:sequence> <xsd:attribute ref="xsd:id"/> </xsd:complexType> </xsd:element> <xsd:element name="project"> <xsd:complexType> <xsd:sequence> <xsd:element ref="xsd:name"/> <xsd:element ref="xsd:status"/> <xsd:element ref="xsd:description"/> <xsd:element ref="xsd:skill" maxOccurs="unbounded"/> </xsd:sequence> </xsd:complexType> </xsd:element> <xsd:element name="coursework"> <xsd:complexType> <xsd:sequence> <xsd:element ref="xsd:class"/> <xsd:element ref="xsd:description"/> <xsd:element ref="xsd:skill" maxOccurs="unbounded"/> </xsd:sequence> </xsd:complexType> </xsd:element> <xsd:element name="job"> <xsd:complexType> <xsd:sequence> <xsd:element ref="name"/> <xsd:element ref="link" minOccurs="0"/> <xsd:element ref="role"/> <xsd:element ref="description"/> <xsd:element name="startDate"/> <!-- substitutionGroup="xsd:date"/>--> <!--commented--> <xsd:element name="endDate"/> <!-- substitutionGroup="xsd:date"/>--> <!--commented--> <xsd:element ref="project" minOccurs="0" maxOccurs="unbounded"/> </xsd:sequence> </xsd:complexType> </xsd:element> <xsd:element name="school"> <xsd:complexType> <xsd:sequence> <xsd:element ref="name"/> <xsd:element ref="link"/> </xsd:sequence> </xsd:complexType> </xsd:element> </xsd:sequence> <!--added--> </xsd:complexType> </xsd:element> <!--added--></xsd:schema>

Anybody can solve this problem? I've tried the following but it gives me error. It is said that "Element 'taxe' occurs more than once in the same content model but does not refer to a top-level type definition. Expected type definition 'xs:integer' but got '{no name}'" It seems that you can't have two elements with the same name but different type. <?xml version="1.0" encoding="UTF-8"?><xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" attributeFormDefault="unqualified"> <xs:element name="root"> <xs:complexType> <xs:choice> <xs:element name="taxe" type="xs:integer"/> <xs:element name="taxe"> <xs:complexType> </xs:complexType> </xs:element> </xs:choice> </xs:complexType> </xs:element></xs:schema>

Hi,I tried the following and it seems that using type=string allows you to have empty attribute. (but if you change to integer, email can't be empty) <xs:element name="myemail"> <xs:complexType> <xs:attribute name="email" type="xs:string" use="required"/> </xs:complexType></xs:element>

I use Altova XMLSpy. You can download the free version (Home Edition). -> http://www.altova.com/support_freexmlspyhome.asp

Hi Aleksanteri, I've tried to run in Altova XMLSpy and Tryit Editor but it doesn't work. I changed the "&&" to "and" but it also doesnt work.

Hi,Thanks, it's working :)I also tried other way which is working, but I prefer your way though /bookstore/book[position()>=2 and position()<=4]

Hi Jojay,What are you trying to return? If you want to return the price and title you can use the following XPath:/bookstore/book[price>35]/(price | title)The result is something like this:<title lang="en">XQuery Kick Start</title><price>50.00</price><title lang="en">Learning XML</title><price>40.00</price>

Hi, Is there any XPath operator to return a range of elements? For example, /bookstore/book[2] will return 2nd book element.How can I return 2nd to 4th book element? I tried /bookstore/book[2 to 4] in Altova XMLSpy 2006 to but instead it returns all book elements (/bookstore/book) :)Thanks :)Btw this is the sample xml: (I took from XPath tutorial) <bookstore><book category="COOKING"> <title lang="en">Everyday Italian</title> ...</book><book category="CHILDREN"> <title lang="en">Harry Potter</title> ...</book><book category="WEB"> <title lang="en">XQuery Kick Start</title> ...</book><book category="WEB"> <title lang="en">Learning XML</title> ...</book></bookstore>

Hi,What is your dtd?I tried the following dtd in XML Spy and it is said that the dtd is valid:<!ELEMENT script (paragraph)+><!ELEMENT paragraph (bold,subparagraph+)+><!ELEMENT subparagraph (bold)><!ELEMENT bold (#PCDATA)>

Hi,For each signature, does it only have one image file? Or a signature can have many images? If it only has one image, I think you can create just one table manager. Then id, sign_id, ... signature are the columns. In signature, just put in the image file name.(Btw I'm also new to XSchema)

Hi,Thanks for your advice. For the result of the selection, I believe tree is good enough. Because XML document itself can be viewed as tree. And since it is GUI, I know the XQuery features it can support will be limited. And the more features I want to include, the more complicated it will be. So I will need to compromise between features and simplicity. (my target users are novice-XML users)Anyway, I haven't come out with the design yet, but I hope I can make a good one :)Regards,Klarinda