Jump to content

Search the Community

Showing results for tags 'mysql_result'.



More search options

  • Search By Tags

    Type tags separated by commas.
  • Search By Author

Content Type


Forums

  • W3Schools
    • General
    • Suggestions
    • Critiques
  • HTML Forums
    • HTML/XHTML
    • CSS
  • Browser Scripting
    • JavaScript
    • VBScript
  • Server Scripting
    • Web Servers
    • Version Control
    • SQL
    • ASP
    • PHP
    • .NET
    • ColdFusion
    • Java/JSP/J2EE
    • CGI
  • XML Forums
    • XML
    • XSLT/XSL-FO
    • Schema
    • Web Services
  • Multimedia
    • Multimedia
    • FLASH

Find results in...

Find results that contain...


Date Created

  • Start

    End


Last Updated

  • Start

    End


Filter by number of...

Joined

  • Start

    End


Group


AIM


MSN


Website URL


ICQ


Yahoo


Jabber


Skype


Location


Interests


Languages

Found 2 results

  1. I have created some custom functions like these: function folder_exists($folder){ global $connection; $sql_folder_exists = "SELECT COUNT(`album_id`) FROM `albums` WHERE `folder` = '{$folder}' LIMIT 1"; $folder_exists = mysql_query($sql_folder_exists, $connection) or die(mysql_error()); return (mysql_result($folder_exists, 0) == 1) ? true : false;} function total_users(){global $connection;$sql_total_users = "SELECT COUNT(`user_id`) FROM `users` ";$total_users = mysql_query($sql_total_users,$connection) or die(mysql_error());return mysql_result($total_users, 0);} , but I decided to use the mysqli_* functions instead. My question is which mysqli_ function is used instead if the mysql_result in these cases??? I've searched through the manual and gives these functions mysqli_data_seek() , mysqli_field_seek() and mysqli_fetch_field(), but when i tried them they did not gave me the expected result and obviously ther's no mysqli_result() function.
  2. divinedesigns1

    error i cant figure out

    ok i ran into an error i can not figure out how to fix and this is the code where the error started function login_check($email, $password){ $email = mysql_real_escape_string($email); $login_query = mysql_query("SELECT COUNT(`users_id`) as `count`, `users_id` FROM `users` WHERE email='$email' AND password='".md5($password)."'"); // the error starts belowreturn (mysql_result($login_query, 0) === 1) ? mysql_result($login_query, 0, `user_id`) : false;} the error started below where i placed a commentim trying to use that return(); to say if a person login info is true or false
×