Regular Expressions

[MrAdam]

Hello. I've been racking my brain for hours trying to work out how, if it's possible, to basically search for every instance of say...

{VAR}

and replace each instance respectively with a value stored in an array, using regular expressions.So for example I have an array like...

$replacements[0]='first instance';$replacements[1]='second instance';

Could anybody help?Cheers! Adam

[Synook]

Not possible with regular expressions. You will need to use a loop in conjunction with other string functions, e.g.

$string = "Your string ready for replacement";$needle = "{VAR}";$replacements = array("first instance", "second instance");$caret = 0;while (strpos($string, $needle)) {$pos = strpos($haystack, $needle);$former = substr($string, 0, $pos);$latter = substr($string, $pos + strlen($needle));$string = $former . $replacements[$caret] . $latter;if ($caret == count($replacements) - 1) $caret = 0; else $caret++;}

Th[e revised edition below] should work.

[MrAdam]

Looks good man cheers. Just one question though, where does $haystack come from? Adam

[Synook]

Oops sorry - revised (correct) edition

$string = "Your string ready for replacement";$needle = "{VAR}";$replacements = array("first instance", "second instance");$caret = 0;while (strpos($string, $needle)) {$pos = strpos($string, $needle);$former = substr($string, 0, $pos);$latter = substr($string, $pos + strlen($needle));$string = $former . $replacements[$caret] . $latter;if ($caret == count($replacements) - 1) $caret = 0; else $caret++;}

[MrAdam]

course yeah... al give it a whirl. cheers for the help! Adam