Disable the current link in a breadcrumb trail

[jelly46]

Does anyone know how to disable the current link in a breadcrumb trail. I am working on a bspoke CMS and i have been asked to remove the current link in the breadcrumb trail. All that i know in XSLT has failed and i have quite some time on, XSLT is no my strength and i need some helpful input. Please help here is the XSLT code:

	<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">	<xsl:output method="html" omit-xml-declaration="yes" /> 	<!--	Variable to determine if the current open page is displayed as a link or plain text	select = 1 - displays plain text link	select = 0 - displays link (default value)	  -->	<xsl:variable name="DisableCurrentPageLink" select="0" /> 	<xsl:template match="BreadCrumbTrail">	<xsl:apply-templates select="Page" />	</xsl:template> 	<xsl:template match="Page">	<span class="BCTDelimiter">»</span>	<xsl:choose>	<xsl:when test="$DisableCurrentPageLink = 1">	<xsl:choose>	<xsl:when test="@IsOpenPage = 1">	<span class="breadcrumb-link">	<xsl:value-of select="@Title"/>	</span>	</xsl:when>	<xsl:otherwise>	<a href="{@URL}" class="breadcrumb-link" title="{@Title}">	<xsl:value-of select="@Title" />	</a>	</xsl:otherwise>	</xsl:choose>	</xsl:when>	<xsl:otherwise>	<a href="{@URL}" class="breadcrumb-link" title="{@Title}">	<xsl:value-of select="@Title" />	</a>	</xsl:otherwise>	</xsl:choose>	</xsl:template>	</xsl:stylesheet>  

[boen_robot]

Everything with this code seems fine at first sight... could you give a sample XML that would be given to this XSLT? Maybe it's an XPath issue (i.e. you're not targeting the nodes you think you're targeting).

[jelly46]

Yeah it does, but I've made an error i need the link hidden or removed.

[boen_robot]

Again - some sample XML please... to help you, I'll need to debug this extensively. Even if indeed that's not the issue, the XML is part of the puzzle non the less.