sikhai Posted December 2, 2019 Share Posted December 2, 2019 Link to comment Share on other sites More sharing options...
Funce Posted December 2, 2019 Share Posted December 2, 2019 Assuming that frm_order is a form, unless you've defined that elsewhere, you need to do $("#frm_order") to access it. There would be a syntax error preventing any further execution. Hence, nothing is done. The second function you want to run, just does the same thing as the first? Clicking a submit button inside a form, is just $("#frm_order").submit() with extra steps. Link to comment Share on other sites More sharing options...
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