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carlruiz07

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About carlruiz07

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  1. Hi. I am very new in XML schema so excuse me in advanced if a making a huge mistake. I am trying to do the following schema, but when i validated with XML Spy there is generating problem about: <xs:element name="CodingSchemeDesignator"> makes the content model non-deterministic against <xs:element name="CodingSchemeDesignator"> . Possible causes: name equality, overlapping occurance or substitution groups. I don´t undersatand what´s going on. I appreciate if someone can give a hand. Thanks. <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" at
  2. Normally you load an XML page and that page sends the data to the XSL file to transform it into XHTML. But can it be done in an other way like loading the XSL page showing the XML document information. Thanks.Carlos Ruiz
  3. I will try. In which format should I open this xslt document. As html or xsl. Thanks Again.Carlos Ruiz
  4. Hi. I am new student of XSLT. After checking the entire XSLT forum, I still haven’t solved my problem. I create a XSLT document from StyleVision and make some work directly in the code using Altova XML spy. This last software gives the chance to make a XSL transformation fast and transparent for me. Right know I would like to do this transformation by myself, loading a XML document in my XSLT document and show it in a internet browser (internet explorer and Firefox).In my XSL document (called plantilla.xsl) I have this <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Tr
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