Jump to content


  • Content Count

  • Joined

  • Last visited

Community Reputation

0 Neutral

About phpnewbie26

  • Rank
  1. Hi, I am working on a website that users can log into from one page and administrate their users from another. first page is index.php and second is admin.php. on the index page I have a form to login with that calls out to a stand alone .php script called "checklogin.php" here is the code... <?php ob_start(); $host=; // Host name $username=; // Mysql username $password="; // Mysql password $db_name="; // Database name $tbl_name="; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db(
  2. The script gets to the //Check Query part and fails. It echos out the "lid query" and doesn't put anything into the database. I tried to just remove that portion, but it still wouldn't input any data into my table. I am very new at PHP and am basically getting code off the internet and throwing it into some pages and seeing if it works. This is a very simple script, I just dont see why it isn't working?
  3. Hi, I am having an Issue inputting data into my database with this code. I tested the connection, which works fine, but when I try to submit the form I get the "die("lid query: " . mysql_error());". Any Ideas? <!doctype html> <html> <head> <meta charset="utf-8"> <title>Untitled Document</title> </head> <body> <form action="thispage.php" method="POST"> <input type="text" name="name" placeholder="Check-in Name"> <input type="submit" value='submit'></form> <?php if (isset($_POST['submit'])) { $name = $_POST
  • Create New...