ale
-
Posts
13 -
Joined
-
Last visited
Content Type
Profiles
Forums
Events
Posts posted by ale
-
-
I know it @justsomeguy, but I cannot understand where I should put it, I mean where in HTML, PHP etc. I read about XML on W3Schools, but there is no clearly explanation for example where I can find an xml doc of some page..
-
Hello guys,
Can anybody tell me some practical example of xml???
I'm new with it. I know what is xml, syntax etc. but I am not so clear with using the same....
Thanks...
-
I think u r right.. Can I do redirect in js??? Actually if I click cancle that return me on the some page???
-
Oh I have a quotes... That is not a problem
-
None of the examples above are working. I tried both of them...
-
Now I do
I will try the examples above... Thanks people for helping me or trying to help
-
Grrrr... I am not good with the AJAX.. I am the beginner
yes I have two buttons... One for submmit and one for the cancelation written directly in my js confirmation box... Here is the code:
Java Script confirmation box code:
<script>function myFunction() {var x;if (confirm("Da li želite da sačuvate promjene?") == true) {x = "You pressed OK!";} else {x = "You pressed Cancel!";}document.getElementById("demo").innerHTML = x;}</script>I know that this is a simple js function.. Do I need make some changes here (write an AJAX into this js code)??? -
I already tried that but there is still some mistake... It is not working...
-
I will try it..
-
Hi
When I am doing the table update I do not see that one article is updated called naziv_artikla. Well, the article is updated in the database when I open my phpmyAdmin, but when I am showing it on the screen, selecting all the articles from the database I do not see the update of naziv_artikla.
Is there problem with the hidden field? I removed it from the code, but then is displayed some error (code is not working properly). Can anybody tells me what should I fix??? Thanks
This is my code for selecting data from the database.
<?php
$con=mysqli_connect("localhost","root","aco123","sifrarnik");// Provjeri konekcijuif (mysqli_connect_errno()) {echo "Failed to connect to MySQLi: " . mysqli_connect_error();}$result = mysqli_query($con,"SELECT * FROM artikli ORDER BY id_artikla ASC");echo "<table border='1'><tr><th>Id artikla</th><th>Naziv artikla</th><th>Cijena artikla</th><th>Na stanju</th><th>Ukupno u KM</th></tr>";while($row = mysqli_fetch_array($result)){echo "<form action = update1.php method = post>";echo "<tr>";echo "<td>" . $row['id_artikla'] . " </td>";echo "<td>" ."<input type = text name = naziv_artikla value = ". $row['naziv_artikla'] . " </td>";echo "<td>" ."<input type = text name = cijena_artikla value = ". $row['cijena_artikla'] . " </td>";echo "<td>" ."<input type = text name = na_stanju value = ". $row['na_stanju'] . " </td>";echo "<td>" . $row ['cijena_artikla'] * $row ['na_stanju'] . " </td>";echo "<td>" ."<input type = hidden name = hidden value = ". $row['id_artikla'] . " </td>";echo "<td>" ."<input type = submit name = update value = Update>";echo "</tr>";echo "</form>";}$ukupno_u_km = $row ['cijena_artikla'] * $row ['na_stanju'];mysqli_close($con);?>And this is my update code.<?php$servername = "localhost";$username = "root";$password = "aco123";$dbname = "sifrarnik";// Kreiranje konekcije$conn = mysqli_connect($servername, $username, $password, $dbname);// Provjera konekcijeif (!$conn) {die("Connection failed: " . mysqli_connect_error());}// Sql upit za update podataka$sql = "UPDATE artikli SET naziv_artikla = '$_POST[naziv_artikla]', cijena_artikla = '$_POST[cijena_artikla]', na_stanju = '$_POST[na_stanju]' WHERE naziv_artikla = '$_POST[hidden]'";mysqli_query ($conn, $sql);// Provjera upitaif (mysqli_query($conn, $sql)) {echo header ("Location: tabela_sa_podacima1.php");} else {echo "Error updating record: " . mysqli_error($conn);}mysqli_close($conn);?> -
There is no selected database because I have removed it. I have a database called sifrarnik. And I do not understand your reply, because I am not looking for that answer.
Well, do I need write an if condition or something in my Java Script code???
I told u, when I click on OK the data is submmited in a database and when I click CANCLE a data is submmited into a database too. I want when I click on CANCLE that nothing is submmited.. That is a point....
-
Hello guys. I am new here. Well, I have some codes written in php. And I have several forms (insert, update etc.).
And I have that confirmation box written in Java Script.
The thing is next: when I click on submmit in my insert form the box shows up and when I click on OK the data is submmited in the database, but when I click on CANCLE the data is submmited too and I do not want that.
Can anybody helps me please???
THIS IS MI INSERT CODE.
<?php$con=mysqli_connect("localhost","root","","");// Provjeri konekcijuif (mysqli_connect_errno()) {echo "Failed to connect to MySQL: " . mysqli_connect_error();}// Varijable za sigurnost$naziv_artikla = mysqli_real_escape_string($con, $_POST['naziv_artikla']);$cijena_artikla = mysqli_real_escape_string($con, $_POST['cijena_artikla']);$na_stanju = mysqli_real_escape_string($con, $_POST['na_stanju']);// Sql upit za insert novih podataka u bazu$sql="INSERT INTO artikli (naziv_artikla, cijena_artikla, na_stanju)VALUES ('$naziv_artikla', '$cijena_artikla', '$na_stanju')";// Provjera upitaif (!mysqli_query($con,$sql)) {die('Error: ' . mysqli_error($con));}echo header ("Location: index1.php");mysqli_close($con);?>THIS IS CONFIRMATION BOX (JAVA SCRIPT).<script>function myFunction() {var x;if (confirm("Da li želite da sačuvate promjene?") == true) {x = "You pressed OK!";} else {x = "You pressed Cancel!";}document.getElementById("demo").innerHTML = x;}</script>
Advice about XML
in XML
Posted
Ok. But why XML is important??? When to use it? Some practic example...