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About RichardZ

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  1. Thanks. I take it then that there is no way to do a percent except manually. I was hoping I could devise a function (perhaps utilizing "this.height"). That, and maybe some concatenation magic (as in " ' " + (this.height*2) + "px'"). But no code wizardry I possible?!?
  2. <!DOCTYPE html> <html> <head> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.2/jquery.min.js"></script> <script> $(document).ready(function(){ $("button").click(function(){ var div = $("div"); div.animate({height: '300px', opacity: '0.4'}, "slow"); div.animate({width: '300px', opacity: '0.8'}, "slow"); div.animate({height: '100px', opacity: '0.4'}, "slow"); div.animate({width: '100px', opacity: '0.8'}, "slow"); }); }); </script> </head> <body> <button>Start Animation</button> <p>By default, all HTML elements have a static position, and cannot be moved. To manipulate the position, remember to first set the CSS position property of the element to relative, fixed, or absolute!</p> <div style="background:#98bf21;height:100px;width:100px;position:absolute;"></div> <div style="background:red;height:50px;width:50px;position:absolute;"></div> </body> </html> Hi All, I've been working through W3 Schools tutorial on jQuery. I worked my way down to the topic on .animate (http://www.w3schools.com/jquery/jquery_animate.asp). For Example 1, of the "Use Queue Functionality", I thought I'd try experimenting with the code, and modified it to add a small red square on top of the large green one (see attached code). I want the red square to change size as the green square changes size, but maintain its size relative to its larger sibling. I can make this happen if I 'ID=' each square and give each the appropriate numeric value, but this isn't exactly flexible/generic. I can use something like '+=100px' and '-=100px', but this clearly adds the same amount to both squares, and naturally the red square doesn't stay relatively sized to the green square. Using something like '*=2.0' just silently fails. Anybody have any suggestions? Thanks, Richard
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