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eneax

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  1. thank you for the help, i'm new to javascript, i'm just learning in this site. Here the code i use to fix the problem: $(document).ready(function(){ $(".infoBox p").hide(); $(".toggle").click(function(){ $(".infoBox p").toggle(); }); $(window).click(function(e) { if (e.target.class != '.toggle' && $(e.target).parents('.toggle').length == 0 && $(".infoBox p").is(":visible") ) { $(".infoBox p").hide(); } }); });
  2. Hello im doing a simple jquery code for let some element of my page be hide or show on click, here my code: $(document).ready(function(){ //hide the box at the start $(".infoBox p").hide(); // open the box when click on class element "toggle" $(".toggle").click(function(){ $(".infoBox p").show(function(){ //close the box by clicking in every part of the window if($(this).is(':visible')) { $(window).click(function(){ $(".infoBox p").hide(); }); } }); }); }); as you can see i want that my element is hide at start, then when i click on element with class toggle it show me the box and at the end when the box is visible, when i click everywhere in the window the box will close. Now the first time everything goes as it should, but from the second time when i click on my element "toggle" it does not show my box, i have to do a double click (why?), the hide on window works fine every times, but i can't understand why the second time i have to double click and not a simple click for open my box. thanks everyone.
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