mich

Thanks, Armed Rebel. i'll try it. thank you once more..

thanks so much for replying me..java script:emoticon('')smilieCan you give an exampple of the code? please?not quite familiar yet..with the php script..java script:emoticon('')smilie

sorry for that, but i was nes to this, and i think that my topic title is not expressing the "HELP"...so i just repost another post with another "please help" title...

First, thanks for taking a look at my post.actually, i'm quite rookie in PHP MYSQL.currently, i'm having this problem. i cant seem to be able to find any help on displayingthe GIF format image where i stored in the MYSQL database as "mediumblob".I've seen many site that teach me the usage of path. but the website i'm working needs the usage of retrieving directly from DATABASE.here's my script sample :(i've select the details, and other details has been called out just the way i expected)but only the image part give me the problems..)<?php...........$sql = "SELECT T_ID, T_NAME, T_PATH, T_GIF, T_CN_CHAR FROM TIANGAN ORDER BY T_ID ASC;";$result = doSql($sql);$query_data = mysql_fetch_row($result);if($result = doSql($sql)){echo "<table width=100% border=0 >";echo "<td width='15%' height='40' align='left'><b><font face='Arial' size =3>Date</b></td><td width='35%' height='40' align='left' ><b><font face='Arial' size =3>Events</b></td><td width='50%' height='40' align='left'><b><font face ='Arial' size =3>Description</b></td></tr>";while($query_data = mysql_fetch_array($result)){$eventid = $query_data[T_ID];echo "<td valign=top><font face='Arial' size ='2'>$query_data[T_NAME]<br><br></td>";header("Content-Type: image/GIF");echo $query_data[T_GIF];......Please HELP?? unsure.gif

First, thanks for taking a look at my post.actually, i'm quite rookie in PHP MYSQL.currently, i'm having this problem. i cant seem to be able to find any help on displaying the GIF format image where i stored in the MYSQL database as "mediumblob".I've seen many site that teach me the usage of path. but the website i'm working needs the usage of retrieving directly from DATABASE. here's my script sample :(i've select the details, and other details has been called out just the way i expected)but only the image part give me the problems..)<?php...........$sql = "SELECT T_ID, T_NAME, T_PATH, T_GIF, T_CN_CHAR FROM TIANGAN ORDER BY T_ID ASC;";$result = doSql($sql);$query_data = mysql_fetch_row($result);if($result = doSql($sql)) { echo "<table width=100% border=0 >"; echo "<td width='15%' height='40' align='left'><b><font face='Arial' size =3>Date</b></td><td width='35%' height='40' align='left' ><b><font face='Arial' size =3>Events</b></td><td width='50%' height='40' align='left'><b><font face ='Arial' size =3>Description</b></td></tr>"; while($query_data = mysql_fetch_array($result)) { $eventid = $query_data[T_ID]; echo "<td valign=top><font face='Arial' size ='2'>$query_data[T_NAME]<br><br></td>";header("Content-Type: image/GIF"); echo $query_data[T_GIF];......Please HELP??