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pritam79

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Everything posted by pritam79

  1. tried a few examples of CSSP, and they were quite useful. But as you said (However, as I just explained, any style rule that can be set in CSS can be accessed and changed using JavaScript), what difference do we get in the two cases (CSSP and JSSS)? because both use Javascript to manipulate a given CSS?
  2. Hi all, this may sound weird but I hv no other option but ask in such a manner, I have been asked to collect some material on the web relating to the topic "LAYERS OF NETSCAPE". but I hv no idea what are "Netscape Layers". the amount of information that I collected from the www is not conclusive enough and does not give a proper explanation of the topic. I really need some help, so plz help me with some relevant web articles....N While Netscape layers are a feature of Netscape 4.0 browsers, and will not be made part of the standard, they allow for interesting effects and creative dynamic HTML pages. I am also including some data relating to this, but i am not sure if these are the ones describing about "Netscape Layers"... The LAYER tag creates layered content. This tag is a Netscape specific tag. This tag is deprecated and is no longer supported by any browser other than Netscape. I recommend that you use z-index to create layers of content using CSS. Layers are a nifty little trick if you have Netscape 4. They act a bit like a z-index in a style sheet, allowing you to place one thing on top of another and give it an exact position on the page. The coding is just the addition of the <LAYER></LAYER> tags to make what you place in between them a layer on the page.<LAYER left="200" top="200" name="bottom"><IMG SRC="scare.jpg"></LAYER>This code would create a layer named "bottom". The contents of the layer is the image in the image tag. The layer would be located 200 pixels from the top of the browser window and 200 pixels from the left of the browser window. This is an exact position on the page, so you may have to adjust the numbers to get the layer where you want it to be. The layer will just sit right over the top of anything in its way, such as text or other images.Now, if you want to place some text over that image, you can use another layer over the top of the image layer, which we named "bottom".<LAYER left="200" top="700" name="bottom"><IMG SRC="scare.jpg" width="100" height="100"></LAYER><LAYER left="200" top="700" name="top"><FONT COLOR="red">I just love to write over the top of my images....</FONT></LAYER> Does this topic include just a theoritical explanation or does it include any explanation through programming like C, C++, Java etc?
  3. Is the one above about using CSS positioning like absolute, relative, fixed etc, OR is it about using javascript to manipulate using the style property? What does this do then? Are both of them the same thing since JavaScript is used in both the cases? please give me an example of both the cases.I got this script that uses JavaScript. Is it an example of CSSP or JSSS?<html><head><title>Dynamic Styles</title><script language="JavaScript">function doChanges(e) { e.style.color = "green"; e.style.fontSize = "20px";}</script></head><body><h3 onmouseover="doChanges(this)" style="color:black;font-size:18px">Welcome to Dynamic HTML!</h3><p>You can do the most amazing things with the least bit of effort.</p></body></html>
  4. Is this script illustrating the use CSS Positioning correct?<html><head><title>Dynamic Positioning</title><script language="JavaScript">var id;function StartGlide(){ Banner.style.pixelLeft = document.body.offsetWidth; Banner.style.visibility = "visible"; id = window.setInterval(Glide,50);}function Glide(){ Banner.style.pixelLeft -= 10; if (Banner.style.pixelLeft <= 0) { Banner.style.pixelLeft = 0; window.clearInterval(id); }}</script></head><body onload="StartGlide()"><h3>Welcome to Dynamic HTML!</h3><p>With dynamic positioning, you can move images anywhere in the document even while the user views the document.</p><img id="Banner" STYLE="visibility:hidden;position:absolute;z-index:-1" SRC="eightball.gif" /></body></html>
  5. I guessed it right. Any links related to this concept? Any links related to this concept? Any links related to this concept? Any links related to this concept?
  6. Hi ALL, I am new to DHTML. I am confused about a few topics as to what they are, and how are they related to DHTML. These topics are- "CSSP (Cascading Style Sheet Positioning)", "JSSS (JavaScript assisted Style Sheet)" and "Layers of Netscape". Do these topics come under DHTML???
  7. Hi all,I am trying this example forthe ErrorDocument directive. Firstly, i have made the following changes to my “httpd.conf” file.I have changed this code of the httpd.conf file ## Customizable error responses come in three flavors:# 1) plain text 2) local redirects 3) external redirects## Some examples:#ErrorDocument 500 “The server made a boo boo.”#ErrorDocument 404 /missing.html#ErrorDocument 404 “/cgi-bin/missing_handler.pl”#ErrorDocument 402 http://www.example.com/subscription_info.html# To this ## Customizable error responses come in three flavors:# 1) plain text 2) local redirects 3) external redirects## Some examples:ErrorDocument 400 /error.php?400ErrorDocument 401 /error.php?401ErrorDocument 403 /error.php?403ErrorDocument 404 /error.php?404ErrorDocument 500 /error.php?500 After this, i have created a file “error.php”- <html> <head> <title>Beginning PHP6, Apache, MySQL Web Development Custom Error Page </title> </head> <body><?phpswitch ($_SERVER['QUERY_STRING']) { case 400: echo '<h1> Bad Request </h1>'; echo '<h2> Error Code 400 </h2>'; echo '<p>The browser has made a Bad Request.</p>'; break; case 401: echo '<h1> Authorization Required </h1>'; echo '<h2> Error Code 401 </h2>'; echo '<p>You have supplied the wrong information to access a secure resource.</p>'; break; case 403: echo '<h1> Access Forbidden </h1>'; echo '<h2> Error Code 403 </h2>'; echo '<p>You have been denied access to this resource.</p>'; break; case 404: echo '<h1> Page Not Found </h1>'; echo '<h2> Error Code 404 </h2>'; echo '<p>The page you are looking for cannot be found.</p>'; break; case 500: echo '<h1> Internal Server Error </h1>'; echo '<h2> Error Code 500 </h2>'; echo '<p>The server has encountered an internal error.</p>'; break; default: echo '<h1> Error Page </h1>'; echo '<p>This is a custom error page...</p>';} echo '<p><a href="mailto:sysadmin@example.com">Contact</a> the system administrator if you feel this to be in error.</p>';?></body></html> But when i open my browser and type http://localhost/nonexistent/page.html, (or any other page that doesn’t reside on my server), into the address bar I don’t get the Page Not Found message on the screen like the one below- Page Not FoundError Code 404The page you are looking for cannot be foundContact the system administrator if you feel this to be in error Instead i get this message- Error PageThis is a custom error page...Contact the system administrator if you feel this to be in error. Why is this not working? plz help...
  8. I have now changed only one line in the file "check_image.php", and now I am getting the desired output. Is the change correct or something more proper is required? The changes that were made have been highlighted using comments. <html><head> <title> Here is your pic! </title></head><body> <h1> So how does it feel to be famous?</h1> <p> Here is the picture you just uploaded to our servers:</p><!--- this line was the original one <img src="images\<?php echo $imagename; ?>" style="float:left;"> --><img src="<?php echo $imagename; ?>" style="float:left;"><!-- this is the new line --> <table> <tr> <td> Image Saved as: </td> <td> <?php echo $imagename; ?> </td> </tr> <tr> <td> Image Type: </td> <td> <?php echo $ext; ?> </td> </tr> <tr> <td> Height: </td> <td> <?php echo $height; ?> </td> </tr> <tr> <td> Width: </td> <td> <?php echo $width; ?> </td> </tr> <tr> <td> Upload Date: </td> <td> <?php echo $image_date; ?> </td> </tr> </table></body></html>
  9. Hi everyone I have a HP script that uploads an image file to the server. I am doing it in the WAMP server locally. It has three scripts as follows-This script is used to connect to MySQL and create the database <?php$db = mysql_connect('localhost', 'root', '') or die ('Unable to connect. Check your connection parameters.');mysql_select_db('moviesite', $db) or die(mysql_error($db)); //create the images table$query = 'CREATE TABLE images ( image_id INTEGER NOT NULL AUTO_INCREMENT, image_caption VARCHAR(255) NOT NULL, image_username VARCHAR(255) NOT NULL, image_filename VARCHAR(255) NOT NULL DEFAULT "", image_date DATE NOT NULL, PRIMARY KEY (image_id) ) ENGINE=MyISAM';mysql_query($query, $db) or die (mysql_error($db)); echo 'Images table successfully created.';?> This html file is used to select the image to be uploaded- <html><head> <title>Upload your pic to our site!</title> <style type="text/css" > <!--td {vertical-align: top;}--> </style></head><body> <form action="check_image.php" method="post" enctype="multipart/form-data"> <table> <tr> <td> Your Username </td> <td><input type="text" name="username"></td> </tr> <tr> <td> Upload Image* </td> <td><input type="file" name="uploadfile"></td> </tr><tr> <td colspan="2" > <small><em>* Acceptable image formats include: GIF, JPG/JPEG and PNG. </em></small> </td> </tr> <tr> <td> Image Caption <br> </td> <td><input type="text" name="caption"></td> </tr><tr> <td colspan="2" style="text-align: center"> <input type="submit" name="submit" value="Upload"> </td> </tr> </table> </form></body></html> And this script is used to do the uploading part- <?php$db = mysql_connect('localhost', 'root', '') or die ('Unable to connect. Check your connection parameters.');mysql_select_db('moviesite', $db) or die(mysql_error($db)); //change this path to match your images directory$dir ='C:/wamp/www/examples/Chapter-7/images'; //make sure the uploaded file transfer was successfulif ($_FILES['uploadfile']['error'] != UPLOAD_ERR_OK) // if file was not successfully uploaded{ switch ($_FILES['uploadfile']['error']) { case UPLOAD_ERR_INI_SIZE: die('The uploaded file exceeds the upload_max_filesize directive in php.ini.'); break; case UPLOAD_ERR_FORM_SIZE: die('The uploaded file exceeds the MAX_FILE_SIZE directive that was specified in the HTML form.'); break; case UPLOAD_ERR_PARTIAL: die('The uploaded file was only partially uploaded.'); break; case UPLOAD_ERR_NO_FILE: die('No file was uploaded.'); break; case UPLOAD_ERR_NO_TMP_DIR: die('The server is missing a temporary folder.'); break; case UPLOAD_ERR_CANT_WRITE: die('The server failed to write the uploaded file to disk.'); break; case UPLOAD_ERR_EXTENSION: die('File upload stopped by extension.'); break; }}//get info about the image being uploaded$image_caption = $_POST['caption'];$image_username = $_POST['username'];$image_date = date('Y-m-d');list($width, $height, $type, $attr) = getimagesize($_FILES['uploadfile']['tmp_name']); // make sure the uploaded file is really a supported imageswitch ($type){case IMAGETYPE_GIF: $image = imagecreatefromgif($_FILES['uploadfile']['tmp_name']) or die('The file you uploaded was not a supported filetype.'); $ext = '.gif'; break;case IMAGETYPE_JPEG: $image = imagecreatefromjpeg($_FILES['uploadfile']['tmp_name']) or die('The file you uploaded was not a supported filetype.'); $ext = '.jpg'; break;case IMAGETYPE_PNG: $image = imagecreatefrompng($_FILES['uploadfile']['tmp_name']) or die('The file you uploaded was not a supported filetype.'); $ext = '.png'; break;default: die('The file you uploaded was not a supported filetype.');} //insert information into image table$query = 'INSERT INTO images (image_caption, image_username, image_date) VALUES ("' . $image_caption . '", "' . $image_username . '", "' . $image_date . '")';$result = mysql_query($query, $db) or die (mysql_error($db)); //retrieve the image_id that MySQL generated automatically when we inserted the new record$last_id = mysql_insert_id(); //because the id is unique, we can use it as the image name as well to make sure we don't overwrite another image that already exists$imagename = $last_id . $ext; // update the image table now that the final filename is known.$query = 'UPDATE images SET image_filename = "' . $imagename . '" WHERE image_id = ' . $last_id;$result = mysql_query($query, $db) or die (mysql_error($db)); //save the image to its final destinationswitch ($type){case IMAGETYPE_GIF: imagegif($image, $dir . '/' . $imagename); break; case IMAGETYPE_JPEG: imagejpeg($image, $dir . '/' . $imagename, 100); break; case IMAGETYPE_PNG: imagepng($image, $dir . '/' . $imagename); break;} imagedestroy($image);?><html><head> <title> Here is your pic! </title></head><body> <h1> So how does it feel to be famous?</h1> <p> Here is the picture you just uploaded to our servers:</p> <img src="images/<?php echo $imagename; ?> " style="float:left;"> <table> <tr> <td> Image Saved as: </td> <td> <?php echo $imagename; ?> </td> </tr> <tr> <td> Image Type: </td> <td> <?php echo $ext; ?> </td> </tr> <tr> <td> Height: </td> <td> <?php echo $height; ?> </td> </tr> <tr> <td> Width: </td> <td> <?php echo $width; ?> </td> </tr> <tr> <td> Upload Date: </td> <td> <?php echo $image_date; ?> </td> </tr> </table></body></html> Now, when I run the 'html' form, the image is selected from any source folder where the image is located. When the "upload" button is then clicked, the image gets uploaded to the "images" folder properly, and the image can be later accessed from the destination folder. but the problem with this script is that after the image is selected and the upload button is clicked the image doesn't appear in the browser whereas the other details of the image like size, dimension etc. get displayed in the browser. Any help plz....
  10. pritam79

    Passing variables

    Which method is the most common, safe, secure, reliable and appropriate to use in order to pass the variables between PHP pages- Using variables in the URL, Through a session, Via a cookie or with an HTML form?
  11. pritam79

    error checking

    The login script worked well and was directing a user to the index page. But suddenly something went wrong and the error message ‘Notice: Undefined variable: _session in C:\wamp\www\Site\login.php on line 13’ appeared. Actually when the login was OK, I was trying to display a welcome message to the user on the index page. But everything went wrong and I am not even able to login. Plz help….
  12. pritam79

    error checking

    What changes are to be made?
  13. pritam79

    error checking

    Hi there, I used $_SESSION["valid_user"] in place of session_register. But after ‘logging in’ the user is not directed to the index page. I think the below function that is in another page is returning 0. This is the function. function check_valid_user() { // see if somebody is logged in and notify them if not global $valid_user; if(isset($_SESSION['$valid_user'])) return 1; return 0; }
  14. pritam79

    error checking

    Thanks, the registration script is working now and a user is directed to the login.php page. But now when I try logging in, I get this error message: Deprecated: Function session_register() is deprecated in C:\wamp\www\Site\login.php on line 13This is login.php<?phpsession_start();if ($_SERVER['REQUEST_METHOD'] == 'POST') { require("posting_fns.php"); if(!filled_out($_POST)) $error['form'] = '<center><font color="red">You have not filled the form completely</font></center>'; if($_POST['username'] && $_POST['password']) // they have just tried logging in { if(login($_POST['username'], $_POST['password'])) { // if they are in the database, register the user id $valid_user = $_POST['username']; session_register("valid_user"); } else // unsuccessful login $error['form'] = '<center><font color="red">You could not be logged in.<br>Check your username and/or password</font></center>'; } if(check_valid_user()) { header('Location: index.php'); } }include "header1.php";?> <div id="content"><?php if(isset($error)){?><?php foreach($error as $key=>$item) echo "<strong>$item</strong></br>"; ?> <?php }?><html><body><table style="width: 768px; height: 195px;"><form action="login.php" method="post"> <tr> <td colspan="2" style="text-align: center; font-weight: 700; font-family: Arial;">Login to start</td> </tr> <tr> <td style="text-align: right; width: 341px; font-family: Arial;">Username : </td> <td style="text-align: left"><input type="text" size="20" name="username"<?php if(isset($_POST['username'])) echo " value = \"{$_POST['username']}\""; ?>></td> </tr> <tr> <td style="text-align: right; width: 341px; font-family: Arial;">Password : </td> <td style="text-align: left"><input type="password" size="20" name="password"> <a href="forgot_form.php">forgot password ?</a> <a href="register.php">not registered ?</a></td> </tr> <tr> <td colspan="2" style="text-align: center"><input type="submit" name="submit" value="Submit"> <input type="reset" name="reset" value="Reset"> </td> </tr></form></table></body></html></div>
  15. pritam79

    error checking

    This is the script that registers a user successfully and inserts everything into the database except the ‘password’.<?phpsession_start();// If form data is posted, run processing scriptif ($_SERVER['REQUEST_METHOD'] == 'POST') { require("posting_fns.php"); if (!(isset($_POST['email']) && valid_email($_POST['email']))) $error['email'] = '<center><font color="red">Not a valid email address</font></center>'; if(!isset($_POST['username']) || (strlen($_POST['username']) < 6 ) || (strlen($_POST['username']) > 16)) $error['username'] = '<center><font color="red">Username must be between 6 to 16 characters<font></center>'; if($_POST['username'] == $_POST['password1']) $error['username'] = '<center><font color="red">Username and Password cannot be same</font></center>'; if(isset($_POST['password1']) && isset($_POST['password2'])) { if($_POST['password1'] !== $_POST['password2']) $error['password'] = '<center><font color="red">Passwords do not match</font></center>'; if (strlen($_POST['password1']) < 6 || strlen($_POST['password1']) > 16) $error['password'] = '<center><font color="red">Password must be between 6 to 16 characters</font></center>'; } else $error['password'] = '<center><font color="red">Password data not found. Possible form error.</font></center>'; if(!isset($error)) { $conn = db_connect() or die('Unable to connect to the database'); mysql_select_db('sitedata', $conn) or die('Could not select database.'); $username = mysql_escape_string($_POST['username']); $result = mysql_query("select * from users where username = '$username'"); if($result) { if(mysql_num_rows($result) < 1) { $password = mysql_escape_string($_POST['password']); $email = mysql_escape_string($_POST['email']); $result = mysql_query("insert into users values('', '$username', '$password', '$email')"); if($result) { $valid_user = $username; session_register("valid_user"); header('Location: login.php'); exit(); } else $error['database'] = '<center><font color="red">An unknown database error has occurred on insert</font></center>'; } else $error['username'] = '<center><font color="red">Username already exists.</font></center>'; } else $error['database'] = '<center><font color="red">An unknown database error has occurred on select</font></center>'; }}include "header1.php";?> <div id="content"><?php if(isset($error)){?><?php foreach($error as $key=>$item) echo "<strong>$item</strong></br>"; ?> <?php }?><form action="register.php" name="register_form" method="post"><br><table style="height: 284px; text-align: left" align="center"> <tr> <td style="width: 204px; font-weight: 700; font-family: Arial;">E-mail address : </td> <td style="width: 290px"> <input type="text" size="20" name="email"<?php if(isset($_POST['email'])) echo " value = \"{$_POST['email']}\""; ?> style="width: 145px"></td> </tr> <tr> <td style="width: 204px; height: 47px; font-weight: 700; font-family: Arial;">Preferred username : </td> <td style="width: 290px; height: 47px;"> <input type="text" size="20" name="username"<?php if(isset($_POST['username'])) echo " value = \"{$_POST['username']}\""; ?> style="width: 145px"> (6 to 16 chars)</td> </tr> <tr> <td style="width: 204px; font-family: Arial; font-weight: 700;">Password : </td> <td style="width: 290px"> <input type="password" size="20" name="password1"<?php if(isset($_POST['password1'])) echo " value = \"{$_POST['password1']}\""; ?> style="width: 145px"> (6 to 16 chars)</td> </tr> <tr> <td style="width: 204px; height: 56px; font-family: Arial; font-weight: 700;">Confirm password : </td> <td style="width: 290px; height: 56px;"> <input type="password" size="20" name="password2"<?php if(isset($_POST['password2'])) echo " value = \"{$_POST['password2']}\""; ?> style="width: 145px"></td> </tr> <tr> <td style="width: 204px"> </td> <td style="width: 290px"><input type="submit" name="Submit" value="register"> <input type="reset" name="Reset" value="reset"></td> </tr></table></form></div></body></html>
  16. pritam79

    error checking

    I have a user registration script in PHP that works OK and inserts the user information into the MySql table. The fields are "uid, username, password and email". uid is the primary key of type integer, username and password are varchar. the problem is that after registering a user all the user details get into the MySq table except the 'password' field. which remains blank in the MySql table. why is it so? plz help.
  17. pritam79

    error checking

    got the script working ok. i m displaying the error messages on top of the form. but how do i display them next to the form fields?
  18. pritam79

    error checking

    When i use if(!$result) {echo mysql_error(); ,I get this error message- Duplicate entry '0' for key 'PRIMARY'
  19. pritam79

    error checking

    This is add_post_form.php<?phpinclude "header1.php";?> <?php // Connect to database if($_SERVER['REQUEST_METHOD'] == 'POST') { $error = array(); $name = (isset($_POST['name'])) ? $_POST['name'] : ""; $title = (isset($_POST['title'])) ? $_POST['title'] : ""; $post = (isset($_POST['post'])) ? $_POST['post'] : ""; if(strlen($name) === 0) { $error['name'] = '<center><font color="red">name cannot be left blank</font></center>'; } if(strlen($title) === 0) { $error['title'] = '<center><font color="red">title cannot be left blank</font></center>'; } if(strlen($post) === 0) { $error['post'] = '<center><font color="red">post cannot be left blank</font></center>'; } if(empty($error)) { $con=mysql_pconnect("localhost","root",""); mysql_select_db("sitedata",$con); $result= mysql_query("SELECT * from sitetable"); $result = mysql_query("INSERT into sitetable(uid, name, title, post) values('', '$_POST[name]', '$_POST[title]', '$_POST[post]')"); header('Location: index.php'); } }?><div id="content"><?php if(isset($error)){?><?php foreach($error as $key=>$item) echo "<strong>$item</strong></br>"; ?> <?php }?> <center><form action="add_post_form.php" method="post"><br><br> Name: <input type="text" name="name"<?php if(isset($_POST['name'])) echo " value = \"{$_POST['name']}\""; ?>><br><br> Title: <input type="text" name="title"<?php if(isset($_POST['title'])) echo " value = \"{$_POST['title']}\""; ?>><br><br> Post: <textarea name="post"<?php if(isset($_POST['post'])) echo " value = \"{$_POST['post']}\""; ?>></textarea><br><br> <input type="submit" value="Submit"> </form></center></div> And this is index.php <?phpinclude "header1.php";?><div id="content"><table bordercolor="white"> <?php $con=mysql_pconnect("localhost","root",""); mysql_select_db("sitedata",$con); $result= mysql_query("SELECT * from sitetable order by uid"); while($row = mysql_fetch_array($result)) { $name = $row['name']; $title = $row['title']; $post = $row['post']; echo "<tr><td width=\"190px\" height=\"128px\"><br>Posted by: $name "; echo "<br>Title: $title </td>"; echo "<td height=\"128px\">$post</td></tr>"; }?></table></div>
  20. pritam79

    error checking

    thanks, it worked, the errors showed. But there is a problem. If there are no input errors, the very first record gets inserted OK. But on subsequent submissions of errorless inputs only the first input is displayed, whereas it should have displayed all the records. The subsequent inputs don’t get inserted in the database table also. Why is it so?
  21. pritam79

    error checking

    i am using this script, but when i click submit, the errors are not detected even when i leave a field empty, and that empty field gets inserted into Mysql table as a blank record. This is the script..<?phpinclude "header1.php";?> <?php // Connect to database if($_SERVER['REQUEST_METHOD'] == 'POST') { if(!(isset($_POST['name']))) $error['name'] = '<center><font color="red">name cannot be left blank</font></center>'; if(!(isset($_POST['title']))) $error['title'] = '<center><font color="red">title cannot be left blank</font></center>'; if(!(isset($_POST['post']))) $error['post'] = '<center><font color="red">post cannot be left blank</font></center>'; if(!isset($error)) { $con=mysql_pconnect("localhost","root",""); mysql_select_db("sitedata",$con); $result= mysql_query("SELECT * from sitetable"); $result = mysql_query("INSERT into sitetable(name, title, post) values('$_POST[name]', '$_POST[title]', '$_POST')"); header('Location: index.php'); } }?><div id="content"><?php if(isset($error)){?><?php foreach($error as $key=>$item) echo "<strong>$item</strong></br>"; ?> <?php }?> <center><form action="add_post_form.php" method="post"><br><br> Name: <input type="text" name="name"<?php if((isset($_POST['name']))) echo " value = \"{$_POST['name']}\""; ?>><br><br> Title: <input type="text" name="title"<?php if(isset($_POST['title'])) echo " value = \"{$_POST['title']}\""; ?>><br><br> Post: <textarea name="post"<?php if(isset($_POST['post'])) echo " value = \"{$_POST['post']}\""; ?>></textarea><br><br> <input type="submit" value="Submit"> </form></center></div>
  22. pritam79

    error checking

    hi everyone, i am using this form to submit the posts made by users. I have not included any error checking here, like if the user leaves a field blank and submits the form. What i want now is that the form should generate error messages whenever the user leaves a field blank and SUBMITS the form, and the error should be displayed right next to the blank text box. I dont want to use javascript, instead i want to do the error checking in PHP as well. thanks to all.........
  23. I recently tried my hand at creating a blog at blogger, but i guess one dose not get the flexibility to create the layout of ones choice there because of many limtations. On the other hand i feel creating an independent site gives one the liberty of experimenting with lot of issues apart from layout, design etc. Is it true?
  24. pritam79

    Asp Comparision

    I dont understand why run away. is ASP that outdated?
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