g_clarkey

cheers for the replies mate, but i managed to get a way to do it.I originally wanted to do it manually as you say, but wasnt allowed too, as "updating two xml files can cause confusion". for who? mutants thats who.server side script i was just about to look into, when i thought i thought id check out the xsl commands for the millionth time and found:<xsl:processing-instruction name="xml-stylesheet"> href="nolsol.xsl" type="text/xsl" </xsl:processing-instruction> Which does exactly what i wanted it two. i cant believe ive wasted a whole day on this!cheers again for the extra thought processes. appreciate it!clarkey.

Hi i have kind changed the way i am doing things a little.I have a XML source.I run a transformation on that to create an rss file.This works fine, my rss worls in my reader, links back to site.My problem is i want the rss to be displayable to people who view the rss outside of a reader (much like the bbc do if you click on their rss).BBC SportI know how to attach the style sheet, just use the line <?xml-stylesheet type="text/xsl" href="nolsol.xsl"?> BUT. as i am creating my rss file from my xml source, i need to write the stylesheet line in my xsl code. What i want my code to look like is:rss.xml: <?xml version="1.0" encoding="ISO-8859-1" ?><?xml-stylesheet title="XSL_formatting" type="text/xsl" href="nolsol.xsl"?><rss version="2.0"> <channel> To do this i have currently this code in my xsl stylesheet:rss.xsl: <?xml version="1.0" encoding="ISO-8859-1" ?><xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method='xml' version='1.0' encoding='UTF-8' indent='yes'/> <xsl:value-of select="title"/> <?xml-stylesheet type="text/xsl" href="nolsol.xsl"?> <rss version="2.0"> <channel> Now currently this outputs:current output: <rss version="2.0"> <channel><title>PWSB RSS</title><link>NewMusicReview.xml</link> <description> Which as you can see doesnt include the stylesheet, and thus displays a tree structure when it is viewed.I am guessing the way i am trying to indicate the rss file has to use the stylesheet is incorrect, currently <?xml-stylesheet type="text/xsl" href="nolsol.xsl"?> just before the rss declaration.Any ideas on how i can go about getting this line to output? If i can get this one line to start of the rss.xml file my work would be done!cheers in advance,clarkey

Hi.I am implementing a website that will have its data in an XML source document.There are goin to be two transformations, one to XHTML, and one to RSS.The one to XHTML works fine, but i have a problem when it comes to RSS. I want to use XSL to create an RSS file from my original XML source.So i will have my xml file, with the link to the rss.xsl transformation at the top. I was hopeing this would display the rss file on screen. I can get it to do this, but it is just as a text file.I want my "text" file to be able to use the stylesheet it references, and to be readable by a rss reader.Have you any general ideas on how to do this?If you need the exact code i will post it.Thanks in advance for any help.