katia
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Everything posted by katia
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For now, my pc is my server, so should I use: "http://localhost/Img/1.jpg" as my path?
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If the picture is on your server, how does it have to be the picture path? Because if the src is like this: "../Img/1.jpg" , pic.width and pic.heigth will return undefined.
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My array contained some elements like: ..Img\album4\321dd.jpg and when I copied it to the javascript array it was all messed up because the "\" . I did put the javascript code in the place where I create the php array, I added some functions for changing the image src value and it works.Thank you guys, I really appreciate your help.
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I keep it there because I need the result of the function when I press the "next" button. The button code is above the code where I create the array.I will work on it more tomorrow.Thank you guys for your help
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It seems that it doesArray ( [0] => ..\Img\album4\37e4.jpg [1] => ..\Img\album4\630e.jpg [2] => ..\Img\album4\delbanchet1.jpg [3] => ..\Img\album4\delbanchet2.JPG [4] => ..\Img\album4\DSC03627.jpg [5] => ..\Img\album4\S3010390.JPG )
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN""http://www.w3.org/TR/html4/loose.dtd"><html><head><title>Slide show</title><meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"></head><script type="text/javascript"> <!--function parseArray(sirpics){sir = new Array();<?phpfor ($i = 0; $i < count($sirpics); $i++)echo "sir[{$i}] = \"{$sirpics[$i]}\";\n";?>alert(sir[0]);}--></script><body><form name="form1" method="post" action="slideshow.php"> <table width="980" height="1045" border="1" cellpadding="0" cellspacing="0"> <tr> <td width="81" height="128"> </td> <td width="800"><table width="797" height="74" border="1" cellpadding="0" cellspacing="0"> <tr> <td width="259"> </td> <td width="277"><input type="button" name="Button" value="Start"></td> <td width="253"> </td> </tr> <tr> <td><input type="button" name="Submit3" value="back" onClick=""></td> <td><input type="button" name="Submit2" value="Stop"></td> <td><div align="justify"> <? $nrpoza=$nrpoza; $numepoza=$numepoza; $album=$album; $opendir = opendir($album); $dim=0; $sirpics=array(); while($fname=readdir($opendir)) { $poza=$album."\\".$fname; $a=split("\\\\\\\\",$album); $nr=count($a)-1; $pozanou="..\\Img\\".$a[$nr]."\\".$fname; if (is_file($poza)) { $sirpics[$dim]=$pozanou; $dim++; } } echo " <input type=\"button\" name=\"Submit4\" value=\"next\" onClick=\"parseArray($sirpics)\"> "; ?> </div></td> </tr> </table></td> <td width="91"> </td> </tr> <tr> <td height="330"> </td> <? $nrpoza=$nrpoza-1; $poza=$sirpic[$nrpoza]; $proba=str_replace("\\\\","\\",$poza); $t_ht=600; $t_wd=seteazaDimensiuni($proba); echo "<td><img name=\"locpoza\" id=\"locpoza\" src=$sirpic[$nrpoza] height=$t_ht width=$t_wd alt=\"\"></td>"; closedir($opendir); ?> <td> </td> </tr> <tr> <td rowspan="2"> </td> <td><? echo $nrpoza." din ".$dim; ?> </td> <td rowspan="2"> </td> </tr> <tr> <td><a href="#">back to albume</a></td> </tr> </table> </form></body></html><?function seteazaDimensiuni($imagine){$imageinfo = getimagesize("$imagine");$t_ht=600;$o_wd=$imageinfo[0];$o_ht=$imageinfo[1];$t_wd=round($o_wd*$t_ht/$o_ht);return $t_wd; } ?>
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After changing this line, I did't get error messages anymore , but when I try to check the result , the alert (ar[0]) returns undefined
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But if I change it to:<? echo " <input type=\"button\" name=\"Submit4\" value=\"next\" onClick=\"parseArray( $picarray )\"> "; ?> and in the Java script I have just an alert function parseArray(picarray){alert(picarray[0]);} or function parseArray(picarray)ar=new Array();<?phpfor ($i = 0; $i < count($picarray); $i++)echo "$ar[$i] = $picarray[$i]";?>alert(ar[0]);} I only get errors
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I do that and I get an error. Why? <? echo " <input type=\"button\" name=\"Submit4\" value=\"next\" onClick=\"parseArray($picnr $picarray )\"> "; ?> and the java script function parseArray(picnr,picarray){ picnr++;document.getElementById('picture').src=picarray[picnr];}
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That's right.
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I'm just trying to read the next value (wich is a picture url )from an array and to dispplay it in an image tag , without having to read the whole picture folder over and over again
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So, I got the array "info' , and "nr" that represents a position in the array . When I submit the form I will increment nr .But when the page reloades nr 's value is the right value but array's value is Array.......
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how can i do that?
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That worked for me. Thanks
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well, i don't want to use ajax too. If I will submit the form, and reload the page, how can I sumbit the array?
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Ok . Can i call a javascript function in a php function?
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I want to change just the image, without refreshing the whole page.I keep my src values of the pictures in an array and when I press a button I want to change the src value of my img tag with another value from the array.
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How can I change the src value when I press a button? Is there any way I can do that in a function?
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I display some images after reading them from a folder, in a while.I sumbmit my form when clicking on an image file. In the new form, I need the file name and the file number in the new from. In my form they are displayed ok ,but since I write these information in a "while" when I submit the file picturenumber will have the last value of $dim, picture name the last value of $fname.Is there any way that I can store these variables so I submit the right values ? $opendir = opendir($album);$dim=0;while($fname=readdir($opendir)){ if (is_file($name)) { $dim++;echo "<td width=\"140\" align=middle >";echo "<input type=image src=$fname name=$fname title=\"$fname\" height=80 alt=\"$fname\" width=120 border=0 value=submit()>";echo "<input type=\"hidden\" name=\"picturenumber\" value=$dim>";echo "<input type=\"hiiden\" name=\"picturename\" value=$fname>";echo "</td>"; }//if} //while closedir($opendir);
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I am using this JScript code to write info in a text file. filename is a string that contains the path to my file (by getting the current directory and then concatenating with the path where the file is)function writetofile(filename,info){var ForAppending=8;var fso = new ActiveXObject("Scripting.FileSystemObject");var ts = fso.OpenTextFile(filename, ForAppending, false); ts.WriteLine(info);ts.Close();}This code works when I test my web page ON my computer. The question is will it work on line?
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When I submit a form I need to load different web pages, acording to some text values the users writes in 2 text boxes : form.textbox1.value and form.textbox2.value . Is there any way I can do that?//this is the piece of my code where i have to do that<form name="formlog" onsubmit="return test(formlog)" action="THECONCATENATEDSTRING ">
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After a lot of searching, I've finalyuy found an example: http://drewsdesigns.50webs.com/js.login.htmSo, it is possible. As I said, is for didactical use and I have to use only client-side
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I did that. The only answer I got was: "use a server-side langauage" and I really have to do it client side
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I have to make photo sharing a web page. I can only use client-side JavaScript and HTML (for didactical reasons), all the information about users and the photos are in folders and files and not in a database.Since I'me very new to this I want to know how to create a login page? Does every user have their own web page with their information? Or can I create the pages dynamicaly , at the moment they log in ,depending on the information I have about the users?