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Farsue

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  1. Farsue

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    Farsue posted a topic in HTML/XHTML

    I was wondering how you get a browser to display an icon next to the url of the webpage. ~Farsue
  2. Farsue
    If someone could explain what exactly this code is doing, I'd really appreciate it. I know it's scaling and moving the image I just don't understand what the point of all the math is and why you wouldn't just pass the value you wanted. confused... thanks for any help :)function moveAndScale(instanceName, targetWidth, targetHeight, targetX, targetY, factor) { instanceName._x += (targetX-instanceName._x)/factor; instanceName._y += (targetY-instanceName._y)/factor; instanceName._width += (targetWidth-instanceName._width)/factor; instanceName._height += (targetHeight-instanceName._height)/factor;
  3. Farsue
    Yea that does look a little sketchy, if the camera did have a cache how would I know and what would you do? Thanks a lot for the help.~Farsue
  4. Farsue
    Thanks for the reply Then this wouldn't be of any use, http://www.datarescue.com/photorescue/ ? Sorry to keep bothering it had my prom pictures on it
  5. Farsue
    I was a complete idiot and deleted my pictures off of the digital camera. I was wondering if there was a way to retrieve this data. I believe you can use a program for this kind of situation on a hard disk, but can it be done with an card? If you could help me out, I'd really appreciate it.Thanks for your time :)and if this post doesn't belong in this section or even in this forum I apologize, don't mean to spam.
  6. Farsue
    http://home.comcast.net/~farsue/dance3.htmlif that doesn't show anything then comcast hates me for using a ton of bandwidth, but thought you'd want to see the fruits of your labor
  7. Farsue
    Thanks for all the help
  8. Farsue
    The remainder then chooses the element in the array?
  9. Farsue
    so I think I'm a re re or something and sorry to take up your time, but in the code document.b1.src = arr[i++%arr.length]; wouldn't "i" eventually equal an amount that was greater than 3 (think there's three in the array) because it's an endless loop? What's stopping it from becoming 4 and then giving an answer of 4/3 or 5/3, you'd get a decimal greater than 1 then and no value for an image.appreciating the help~farsue
  10. Farsue
    so if I had 4 images it would limit the amount of source files to 4? That way you wouldn't get a non-existent file? Why couldn't you have something greater than the array length?
  11. Farsue
    It still says error on the page, don't know. I checked my images they're alright. Just out of curiosity what are you doing with the array and why is i being divided by it? sorry I'm a complete newbie.EDIT:never mind you're a genius it works thanks. I'd still like to know what the array does if you don't mind.
  12. Farsue
    I don't know if it's possible to do, but can you using javascript tell it to replace the current image by a new one every 2 seconds or any amount of time? Almost like a side show or frames for a movie. The code I have so far is listed below. Any help would be greatly appreciated, kind of new. <html><head><script type="text/javascript">function timedImage(){var t1=setTimeout("document.b1.src ="novas(base)web.jpg",2000)var t2=setTimeout("document.b1.src ="novas(secondframe)web.jpg",4000)var t3=setTimeout("document.b1.src ="novas(thirdframe)web.jpg",6000)}</script></head><body><form><input type="button" value="dance" onClick="timedImage()"><img border="0" alt="Visit W3Schools!" src="novas(base)web.jpg" name="b1" width="800" height="800" /></form></body></html> ~Farsue
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