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westman

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Posts posted by westman

  1. most impotent question has been asked

    "What are you trying to do?"

     

    are you posting info to a DB or are you link building?

     

    from your code it is uncertain.

  2. thank you it works.

     

    you got me!

     

    it is not my code but I have used it before and it has worked outside a loop.

     

    would love to know how each line of the code works.

     

    have you got the time?

  3. try...

    $mailtext .= '<b>' . $name . '</b>' . $trenner . $einzelwert . $trenner2;or$mailtext .= '<strong>' . $name . '</strong>' . $trenner . $einzelwert . $trenner2;

    as mentioned above.

  4. $to = "me@gmail.com";	$from = "admi@mysite.com";$subject = "error";$message = '<html>		<body bgcolor="#FFFFFF">		<br /><br />        Error: ' . $error_log . '		</body>		</html>';		// end of message		$headers = "From: $fromrn";		$headers .= "Content-type: text/htmlrn";		// Finally send the activation email to the member		mail($to, $subject, $message, $headers);

    NOTE to the mods and admin.

    It is ok to help with code from time to time it will not kill you to help in this way.

  5. I do not know what part of my code defines the function so here is what I did...

    $time04 = date("Y-m-d",time() - (60*60*24*7*26)); // 6.5  mouths (26 weeks)$time04 = mysql_real_escape_string($time04);function delete_directory($directory, $empty=false){  if(substr($directory,-1) == DIRECTORY_SEPARATOR){    $directory = substr($directory,0,-1);  }    if(!is_dir($directory) || !is_readable($directory)){    return false;  }    else{    $handle = opendir($directory);    while (false !== ($item = readdir($handle))){      if($item != '.' && $item != '..'){        $path = $directory.DIRECTORY_SEPARATOR.$item;        if(is_dir($path)){          delete_directory($path);	}        		else{          unlink($path);        }      }    }    closedir($handle);     if($empty == false){      if(!rmdir($directory)){        return false;	}    }    return true;	}}	$sql02_info_get = mysql_query("SELECT * FROM ads WHERE live='0' AND addate < TIMESTAMP('$time04')");$sql02_info_get_count = mysql_num_rows($sql02_info_get);if ($sql02_info_get_count > 0){while($row = mysql_fetch_array($sql02_info_get)){$remove_adid = $row["adid"];$directory = "pics/$remove_adid";//if(!is_dir($directory)){//echo "good";//exit();	//}else{//echo "bad";//exit();	//}delete_directory($directory);$remove_adid = mysql_real_escape_string($remove_adid);$sql02 = mysql_query("DELETE FROM ads WHERE adid='$remove_adid'"); } // end loop}

    will this work?

    if not please give code examples.

  6. how am I going to remove the code in the block that defines the function and still have a function than functions?

     

    I do not understand.

     

    please be more clear by telling me all the key words I need to remove or paste some code to see.

  7. Hi all,

    I am trying to remove a folder if it exists and files within it if they exists.

     

    I keep getting this error.

     

    Fatal error: Cannot redeclare delete_directory() (previously declared in /home/content/31/1234321/html/ads/index.php:236) in /home/content/1234321/html/ads/index.php on line 236

    $time04 = date("Y-m-d",time() - (60*60*24*7*26)); // 6.5  mouths (26 weeks)$time04 = mysql_real_escape_string($time04);$sql02_info_get = mysql_query("SELECT * FROM ads WHERE live='0' AND addate < TIMESTAMP('$time04')");$sql02_info_get_count = mysql_num_rows($sql02_info_get);if ($sql02_info_get_count > 0){while($row = mysql_fetch_array($sql02_info_get)){$remove_adid = $row["adid"];$directory = "pics/$remove_adid";//if(!is_dir($directory)){//echo "good";//exit();	//}else{//echo "bad";//exit();	//}function delete_directory($directory, $empty=false) // line 236{  if(substr($directory,-1) == DIRECTORY_SEPARATOR){    $directory = substr($directory,0,-1);  }    if(!is_dir($directory) || !is_readable($directory)){    return false;  }    else{    $handle = opendir($directory);    while (false !== ($item = readdir($handle))){      if($item != '.' && $item != '..'){        $path = $directory.DIRECTORY_SEPARATOR.$item;        if(is_dir($path)){          delete_directory($path);	}        		else{          unlink($path);        }      }    }    closedir($handle);     if($empty == false){      if(!rmdir($directory)){        return false;	}    }    return true;	}}	delete_directory($directory);$remove_adid = mysql_real_escape_string($remove_adid);$sql02 = mysql_query("DELETE FROM ads WHERE adid='$remove_adid'"); } // end loop}

    any help?

  8. I know the logic but not the code.

    so hopefully this question helps.

     

    how do a make this variable hold the current time in London (in "Timestamp" format and "Date Time" format)?

    $The_Time_In_London_Is

     

    from this basic platform I may be able to do the maths.

  9. Hi there,

    I have been playing around with this code...

    $t = strtotime('Friday 18:30');$seconds_until_t = $t - time();$t2 = strtotime('Friday 18:30');$seconds_until_t2 = $t2 - date_default_timezone_set("UTC");echo $seconds_until_t * 1000;echo "<br />";echo $seconds_until_t2 * 1000;$TimeZoneNameFrom="UTC";$TimeZoneNameTo="Europe/London";

    and I have a problem with my timestampthe problem is that when I get "echo $seconds_until_t * 1000;" I see the numbers 41550000

    but when I copy and past it in JavaScript

    I get a long negative number and this feedback...

     

    Do It Result: java.util.GregorianCalendar[time=384847000,areFieldsSet=true,lenient=true,zone=Europe/Istanbul,firstDayOfWeek=2,minimalDaysInFirstWeek=4,ERA=1,YEAR=1970,MONTH=0,WEEK_OF_YEAR=2,WEEK_OF_MONTH=2,DAY_OF_MONTH=5,DAY_OF_YEAR=5,DAY_OF_WEEK=2,DAY_OF_WEEK_IN_MONTH=1,AM_PM=1,HOUR=0,HOUR_OF_DAY=12,MINUTE=54,SECOND=7,MILLISECOND=0,ZONE_OFFSET=7200000,DST_OFFSET=0]

     

    Again I am trying to get a timestamp for how many days, hours and minutes are left till the next Friday 18:30 in London.

     

    or to make thinks even easier, to get my php to print out the next Friday 18:30 in London like this "01/23/2015 18:30"

     

    what am I doing wrong?

  10. I really do appreciate your examples, they are helpful.

    However, I am using App Inventor to build an app and can not use hard core code.

     

    The variable I am using in App Inventor is:

    day = 6

    hour = 18

    minute = 30

    and the count down works

     

    https://lh3.googleusercontent.com/-rToyVjegrJ4/VK7brlHiFgI/AAAAAAAAGFA/e9NkeE9Y5Nc/s1600/Capture.JPG

     

    Capture.JPG

    the only problem is that it takes the time from the phone.

    That's why I need to use php to call the UTC+0 time.

     

    How can I get the UTC+0 time in the format of...

    day = 6 (days remaining)

    hour = 18 (hours remaining)

    minute = 30 (minutes remaining)

    in php?

  11. in this echo i am getting "-" in the number

    for example "-384847000"

     

    why?

     

    plus here i have 3848 minutes till the next Friday 18:30

    Ho do I change this long number

    from "-384847000"

    to "day = 4 hours = 2 minutes =45"

     

     

    I tried this but it did not work....

     

    $t = strtotime('Friday 18:30');

    $seconds_until_t = time() - $t;
    $minutes = $seconds_until_t / 60;
    $hours = $seconds_until_t / 60;
    $days = $seconds_until_t / 24;
    echo $seconds_until_t * 1000;
    echo "<br />";
    echo $minutes * 1000;
    echo "<br />";
    echo $hours;
    echo "<br />";
    echo $days;
    echo "<br />";
  12. I am looking for "Friday" witch = 6 in JavaScript.

    I have a count down in JavaScript and i need php to give the day and hour to JavaScript so the count down is the same all over the world.

     

    The day "Friday (6)"

    The hour "18"

    The minute "30"

  13. I am working in JavaScript and need to past the time in a URL from php

     

    so the day will be a number from 1-7 (1 = sunday) and the time (for example 13:32)

     

    so i need the day and hour in 2 different php variables

     

    could you give an example?

  14. hi all i have been trying for 7 hours now and i can not find the best way to change 20% from a url string to a space.

    I am trying to change this "20%" to this " ".

    this is what i have....

    $new_url = preg_replace('"20%"', '" "', $new_url); 

    any help?

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