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  1. Hi everybody, I am trying to import a db in myphpadmin which works fine on another server and I get the error below. Can you tell me what's wrong here? Thank you. Roughly translated it s: Static analysis: 1 error was found during analysis. Keyword not recognized. (near "ON" at position 25) SQL Query: SET FOREIGN_KEY_CHECKS = ON; MySQL message: #2006 - MySQL server has gone away
  2. I dropped a column (linknum) in a table (wine) with mysql in the console After that I wanted to make it again ALTER TABLE wine ADD linknum INT DEFAULT '1' NOT NULL AUTO_INCREMENT PRIMARY KEY FIRST; but now I recieve an error message like this: ERROR 1067 (42000): Invalid default value for 'linknum' How can I solve it, and create a column called linknum again, starting with 1 and incrementing 1 ?
  3. This is my situation If variable $conn has all variables (with a value) $conn = new mysqli($servername, $username, $password, $dbname); and then you use var_dump($conn); and the output would be null of all the values of $conn. What would it mean? Am I right the connection then needs to be re-established? I'm doing 2 queries on a database. First query is SHOW TABLES then make the user choose a table value. From this value a new query is done. So first connection is done. But can I use this connection or should I make a new one?
  4. I have a question about security and MYSQL. I installed MYSQL and PHPMYADMIN. I changed the root password. But when in PHPMYADMIN I see a list of users and priviliges. Usernames sound like: All, root or pma. I understand I need pma or root, but what is the use of All ? User name Host Password Global privileges User group Grant Action Any % -- USAGE Any localhost No USAGE pma localhost Yes USAGE root 127.0.0.1 Yes ALL PRIVILEGES root ::1 Yes ALL PRIVILEGES root localhost Yes ALL PRIVILEGES
  5. //Determine who receives bracelets and update bracelet recipients table //This is only applicable to recipients of CHARMS $sql = "SELECT DISTINCT ACCOUNT_NUM FROM sc_master WHERE REFERENCE = '$reference' AND AWARD NOT LIKE 'Scentsational Start Award%' AND GIFT_GROUP = 'Charm' AND PROCESSED <> 'X' LIMIT 1000"; $qry = mysql_query($sql) or die(mysql_error()); while($r = mysql_fetch_array($qry)) { $acct = $r['ACCOUNT_NUM']; $fname = $r['FNAME']; //no data due to DISTINCT clause $lname = $r['LNAME']; //no data due to DISTINCT clause $bsql = "SELECT ID FROM sc_bracelet_reci
  6. So my goal is now to have a table list read from the database. The content of the table is supposed to be put in an <SELECT> <OPTION VALUE> form for a dropdown menu having the user select only 1 value. $conn = new mysqli($servername, $username, $password, $dbname); if ($conn->connect_error) { die("Connection failed: " . $conn->connect_error); } $sql = "SHOW TABLES"; if (!$result = $conn->query($sql)){ die('There was an error running the query[' .$conn->error. ']'); } foreach($row = $result->fetch_assoc()){ echo "<
  7. id | mid | pid | owgh | nwgh |1 3 12 1.5 0.62 3 12 1.5 0.33 3 14 0.6 0.44 3 15 1.2 1.15 4 16 1.5 1.06 4 17 2.4 1.27 3 19 3.0 1.4 Select mid , COUNT(distinct pid) as cpid , SUM(nwgh) as totalnwgh from test GROUP BY mid sqlfiddle : link of below result with above query mid cpid totalnwgh3 4 3.84 2 2.2 But above i need one more column that's as below : **totowgh** mid cpid totalnwgh totowgh3 4 3.8 6.3 (DISTINCT value as per pid column)4 2 2.2 3.9 where totowgh
  8. tech991

    Bookmark system

    Hi to all. I'm new in php development. I'm trying to do a bookmark system. I have an intern search engine that extract data from a database table build in MYSQL that show as link and the user can click on and appear es text html. I want to give the possibility to add a star button near these link and when the user click on to bookmark. I found 2 ways to do this, but I'm sure that exist more solution that can do better or not: 1- Give the possibility to the user that when click on button near the link that extract data from the database to add this on a bookmark table. 2- When the user
  9. Hello. I'm currently developing an app in the Intel XDK for my local high school. One of the features I would like to add is something where school administrators (such as the athletic director) can login and then submit data into an HTML5 form, which is then submitted to a server and stored in a database. Then, after it is stored, I would like the information to be able to be viewed by regular users of the app, in something such as an HTML page. THe purpose of this would be for the school admins to submit scores from the games such as football, etc. My question is, how do I setup the server (
  10. Hi Sir, I creating a form with checkbox for example I checked the Add Employee and Upload Employee, after I click the Submit button the output is 2 and 3 which is correct but only the Upload Employee was checked. How can it be that the Add Employee and Upload Employee was checked. Also how can save checkbox check in the database. if(isset($_POST['submit'])){ if(!empty($_POST['access'])) { $access = $_POST['access']; echo "You chose the following color(s): <br>"; foreach ($access as $access_id){ echo $access_id."<br />"; }} // end brace for if(isset else {
  11. Hello every one anyone can solve my prob my database not save my html data in mysql i want to save my hrml data in mysql but its work only for 755 characters after 755 755 no data save in database so plz tell me how i save my html 8000 characters data how to save in my db Thanks
  12. Hi, Can anyone recommend anywhere that I can learn code part time in the United Kingdom? I have been teaching myself html, css, etc on a basic level & now venturing into php, mysql, js, etc & think that having a tutor or guidance would really help speed up my learning process. Any companies or colleges offering part time courses in these area's will hopefully fill in the holes in my knowledge & help me progress. I'm not really concerned about qualification certificates, the knowledge is more important to me. Thanks for any advice. Old Guy.
  13. Hi, need some advice to do logic in my table casue i never face this before, hope you guys help me out this issue i need to show data from database and the image upload here cause cannot upload here to big system respond but let me tell here what i stuck it I need show the row with max id ( Done ) I need show data limit 1 where id != row with max id (Done) I need show all data without max id (point 1) and point 2 Thanks, and think that it can handle by css by hidden or by selector asecending but still figure out how. edit : i use codeiigniter
  14. Hi,Good day!I found a tutorial on creating a calendar that can add Event.Now, I want to enhance it to add Delete and Edit button but I have no idea on how to do that here is my code:calendar.php <?php$hostname = 'localhost';$username = 'root';$password = 'root';$dbname = 'calendar';$conn = new mysqli($hostname, $username, $password, $dbname);// Check connectionif ($conn->connect_error) { die("Connection failed: " . $conn->connect_error);}?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmln
  15. Hi, i am playing a game and there is a user in chat that bothers me and other players a lot but he does not break any game rule... i was wondering if there is a way i could block or mute his text with a JavaScript if so, does anyone have a tutorial on how to code something like this? the chat have no ID but every chat message is put out like this. <table border="0" padding="0" cellspacing="0" width="100%"> <tbody> <tr> <td width="90" class="chat"> <div id="202525"></div> 2015-08-24 0
  16. I get an error code You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near I found this is error 1149 ? is that right? I'm looking for the meaning of this error. What is the reason I'm having this? Does it mean the mysq code in my php script is wrong? Is a solution changing the MYSQL line or can the error also be made in the php part of the script?
  17. Bootstrap sounds a bit like a finished optional program to use? also It seemed like when I first started seeing this page I have been learning from, that it is trying to "sell me" on the HTML5 as a good new and easier way to think of html code I wonder if this stuff has any merit? is it true? Is there any particular Web and computer code language *(scripting etc,) that are universal, or more functional for a different similar type? like for example I have read that someone wrote "there personal favorite scripting is" and similar quoted. Is there any that are not liked or favored by ma
  18. I'm receiving this error 'Call to a member function prepare() on null' if I were to put this search code into the page. It works fine if i were to put at other pages(for inserting to database).Here's my search code that I've put before the html tags: <?php//echo '<pre>';//echo $_POST;//echo '</pre>';//declare the form name//$searchForm = htmlentities($_SERVER['PHP_SELF']);try { //inserts database connections require('Connections/database.php'); if (($_SERVER['REQUEST_METHOD'] == 'POST') && isset($_POST['search'])) { // array to hold errors $errorsSearch = array(); //
  19. Hi,Good day!I created a search box and my problem is when I type Employee ID the auto list displayed is Employee Name, I need to display on the list is based on what I type. I don't know if it is possible that in one search box I can search Employee name then the list of names will display, when I type Employee ID, employee id list will display. same with Passport no and res id.Now, when I type Employee Id or Passport No or res id and employee name. the displayed list is employee name.this is my code: <script type="text/javascript" src="js/jquery.js"></script> <script type=
  20. I'm trying to restrict users from accessing a page if their rank isn't manager or admin. I made a variable called $rank which is the rank that is fetched from the user's table in my database. When I echo the rank on the page, the rank does equal to manager or admin but it redirects me to the index page because it somehow doesn't equal manager or admin. When I try using this code: if(!isset($_SESSION['userID'])) { header("Location: index.php");} else if ($rank == "manager" OR $rank == "admin") { } else { header("Location: index.php");} it does work but I feel like that's the wrong way of doin
  21. I have a hard time trying to make my radio buttons work. I know that radio buttons are a special case whereby if the user did not click on them, the value will not be taken in. Thus, i have made all my radio buttons to be set per group. However, i can't seem to get the validating right. This is my current validating code as of now: if ((isset($data['specialization']) && $data['specialization'] = "specialization_1")) { $data['specialization'] = "IS"; $skillset =($data['ISgrp1'].",".$data['ISgrp2'].",".$data['ISgrp3'].",".$data['ISgrp4'].",".$data['ISgrp5']); } if ((isset($data['
  22. I'm creating a simple login and registration form. What I'm trying to do is when a user registers, it should log them in. In order to get logged in, the user's ID that gets registered needs to be sent to the home page so the username can be displayed. I'm not sure what is wrong with my code. Register: <!DOCTYPE html><?php session_start(); if(isset($_SESSION['userID']) AND !empty($_SESSION['userID'])) { header("Location: home.php"); } if(isset($_POST['register'])) { $firstName = mysqli_real_escape_string($dbConnect, $_POST['firstName']); $lastName
  23. I am trying to make a result page so I can get some information from the database by using php coding. I need it to be able to find a patient name and date of service. Which will be if I type in (Search:) Joe Doe and add (from:) 02/02/2015 (to:) 02/14/2015. It will find the patient name and all date of service. Here is my code ... I know mysql is not good but it will work for now. <?phpmysql_connect('localhost', 'root', 'no_password');mysql_select_db('timeclock');$results = array();if(isset($_GET['search'])) { $search = $_GET['search_box']; $from = $_GET['from']; // or $from = $
  24. Hi, I have doubt in AJAX Database, In that getuser.php what should i write in the place of ajax_demo. Please anybody help me. And the link is http://www.w3schools.com/php/php_ajax_database.asp
  25. I'm writing an application using PHP and MySQL that is a TV Guide/TV Listings to pull the results of the following fields: id – int(11) name – varchar(255) chan_position – int(3) src_image – varchar(255) time – varchar(255) title – varchar(255) date – varchar(25) This is the code I've tried so far that basically displays all results as a table: <?php require('db.php'); ?> <div class="container"> <? //Start table echo "<table id='guide'>"; echo "<th>Channel</th>"; echo "<th>Title</th>"; e
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