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Found 5 results

  1. Hello, I have a question about how to send form data to the database, without reloading the entire page. I discovered working with xmlhttprequest. I managed to show text from another file by implementing a javascript function with xhr into my script. I don’t know much about javascript and don’t understand how a javascript form should be added to an existing function. Finally this should run a php script executing the code to add the form data to the database. <!DOCTYPE html> <html> <body bgcolor="grey"> <center>
  2. This is my Javascript code: var Data_Display var My_Data function Setup() { My_Data = new XMLHttpRequest(); My_Data.open("GET","http://localhost:8080/exist/rest/db/apps/HTML_Student/Database_Example.xq"); My_Data.send(); document.getElementById("Information").value = My_Data.responseXML; } This is my XML code: <xml> <svg> <svg_data>100</svg_data> </svg> </xml> This is my XQuery: xquery version "3.0"; for $Data in doc("Database_Example.xml")/xml/svg/svg_data where $Data = 100 return $Data When I ran the Javascript code, the com
  3. I am trying to fetch some images from a server, however I need them to come back in the order requested. Currently, the below returns the images back in a seemingly random order, I guess which ever are finished first. How can I ensure I get the images back in the order they were requested? var xhr = [];for (i = 0; i < count; i++){ (function (i){ xhr[i] = new XMLHttpRequest(); xhr[i].open( "GET", url + dir + "/" + i.toString() + ".png", true ); xhr[i].responseType = "arraybuffer"; xhr[i].onreadystatechange = function () { if (xhr[i].readyState == 4 && xhr[i].status == 2
  4. I'm trying to convert: http://techslides.com/demos/image-video/create.html to work with images on a server. Currently the demo above uses local files: if(filesarr.length>0){ //loop through them and process for(i=0; i<filesarr.length; i++) { var file = filesarr[i]; if(file.type.match(/image.*/)){ process(file); } else { document.getElementById('status').innerHTML = "This file does not seem to be a image.";
  5. Hello, im trying to create a nice file uploader using XmlHttpRequest so that we can get a nice progress bar and stuff without reloading the page. When I try to upload using my code the progress bar does show and count % up untill completed but no file is being uploded. I will show you my code and tell you what I think is wrong, but I will strip it down a bit. This is my js part: function uploadFile() { var xhrObj = new XMLHttpRequest(); var filesToBeUploaded = document.getElementById("fileControl"); var file = "filename="+filesToBeUploaded.files[0]; xhrObj.upload.addEve
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