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Found 5 results

  1. Hi all, I have a php file to check a users input and it seems pretty straight-forward as far as logic goes, but the variable seems to be concatenating the "badEntry" onto its return value. I've been over it and over it and can't seem to see what's wrong. I originally had $userInput as the only return variable, but when I started having trouble I added the $toReturn variable to hopefully make it clear what I was doing wrong. Didn't help. I enter 'sakde12345' and I get that back with 'BadEntry' concatenated to it - looks like this - sakde12345BadEntry. My callback function is supposed
  2. How to write GROUP_CONCAT_MAX_LEN Increasing as per requriement in perticuar select query in php.....
  3. how to increase group caoncat length in sql quaries.....? please give me suggestions........
  4. Hello guys, i need some basic info here. I need to build string, which must be builded into "'%name%'", when name is a variable. Using concat, its easy to do that:String myString = "'%" + name + "%'";how to do that with String.format() ?I`m trying to do like: String myString = String.format("'%%s%'", name); << it appears a problem with "%'" tag. how to avoid that ? How to use double %`s in the quotas ?Any suggestions ? Linas.
  5. ibrahimjan

    CONCAT sql

    Hi All, I got this sql connection to my table wb, it all seems to work fine in phpmyadmin, when testing sql, but when i want to us it, it comes up with: Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING inC:\----------\test3.php on line 75 line 75 is the $query_wb $query_wb = "SELECT CONCAT( "[", GROUP_CONCAT( CONCAT("{weID:'",`weID`,"'"), CONCAT(",weName:'",`weName`,"'}") ) ,"]") AS json FROM wb;"; any Ideas how to make it work??
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