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Found 6 results

  1. Hello This is my site: http://hojalateriaelguante.agencialosnavegantes.cl/ I need the row with the blue background row ("proporcionamos la mejor solución...") to be full-width like in the attached picture but i don't know how. Extra information: This is a wordpress theme and i'm using a page builder, the div i have to change its width is a row inside a section that has its own image background, so the row is an inner row of this section and that's why i think is not possible for the section with the blue background to use the screen's full width. How can i override that? i don't kn
  2. I am working on a landing page that has two horizontal columns in bootstrap. Everything works well except that I cannot vertically align the "COMING SOON" text in the top box without separating the 2 boxes and leaving a gutter between them. I would like to vertically center the text in the top column. Any help will be highly appreciated. Below is the code: <!DOCTYPE html> <html lang="en"> <head> <meta charset="utf-8"> </head> <style> body{ background-color : #222 !important; /*background-color :
  3. Hello. This is my page: http://feriapixel.cl/anchour/ I'm using Bootstrap's grid system and whenever i use divs with the row class they get stuck in a container, and i want them to use be full width. This is one of my divs for example: <div class="content-seis" > <div class="row" > <div class="col-sm-6 showroom coffee-break" > <h2>Un coffee break con sabor y atención casera, para tu trabajo</h2> <p>Café americano, tapaditos, fruta, jugos, opciones vegetarianas y más. Tenemos promociones ya armadas, pero tomamos tu pedido con gusto
  4. i found this script online: http://stackoverflow.com/questions/8022353/how-to-populate-html-dropdown-list-with-values-from-database <?php $conn = new mysqli('localhost', 'username', 'password', 'database') or die ('Cannot connect to db'); $result = $conn->query("select id, name from table"); echo "<html>"; echo "<body>"; echo "<select name='id'>"; while ($row = $result->fetch_assoc()) { unset($id, $name); $id = $row['id']; $name = $row['name']; echo '<option valu
  5. Hello, To start, sorry for my english i'm French ^^ I have a problem, in fact I can't retrieve the index of the row in a table. I tried many things but I haven't found the solution. Here is my code: <script id='TableSuser'> var oTableSuser = new sap.ui.table.Table({editable:false, width: "400px", visibleRowCount:2}); var oControl = new sap.ui.commons.Button({text : "{suser}", press : function() {openDialog(oTableSuser.getSelectedIndex());}}); oTableSuser.addColumn(new sap.ui.table.Column({label: new sap.ui.commons.Label({text: "Suser"}), template: oControl, sortProperty: "But
  6. funbinod

    edit a record

    (feeling a bit difficult to describe) i am trying to edit a post on a mysql table. in it data is transferred from one row to previous data was recorded for "ID-1" and now data on some cell should be transferred to "ID-2" and that makes change to another table also. i succeeded to change data on another table and change on "ID-2". but i got difficulties to retrieve "ID-1" to change its value. the edit form is like this --- <form method ="POST" action="saleseditpost.php"><fieldset><legend><h1>Edit Sales Record</h1></legend><div class="form-field
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