simple send

[user4fun]

Onclick function getinfo is ranit sends var picked to get_def.phpget_def.php prints $found_defthe text area needs to be updated??What am i doing wrong?

function GetInfo(){   document.getElementById('text').value = "Loading...";	init_ajax();	xmlHttp.onreadystatechange = changetext;	var picked = document.getElementById('choice').value;	xmlHttp.open("GET", ","get_def.php?choice=" + picked,true);	xmlHttp.send(null); }function changetext()		{		 document.getElementById('text').value = xmlHttp.responseText;		}	   </script>

[Synook]

What does the init_ajax() function look like?

[user4fun]

var xmlHttp;function init_ajax(){  try  {	xmlHttp=new XMLHttpRequest();  }  catch (e)  {	try	{	  xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");	}	catch (e)	{	  try	  {		xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");	  }	  catch (e)	  {		alert("Your browser does not support AJAX!");	  }	}  }}

That is it

[Synook]

You have a slight syntax error on the xmlHttp.open() line, it should look like

xmlHttp.open("GET", "get_def.php?choice=" + picked,true);

[user4fun]

??????????????????????????????//That is all I have to say about that?? lolThank you, I am an idiot.It is always good to get a fresh set of eyes.

[Synook]

You should get FireFox and FireBug, together they will debug your JavaScript at runtime, so you can pick up errors immediately.