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Warning: mysql_select_db(): 1 is not a valid MySQL-Link resource


coolgamer48
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When I try to run this script:

<html>	<body>		<form action = "mysql_test2.php" method = "post">			First Name: <input type = "text" name = "firstname" /><br />			Last Name: <input type = "text" name = "lastname" /><br />			<input type = "submit" value = "Submit" />		</form>		<?php			$con = mysql_connect("fdb1.awardspace.com","coolgamer48_sql1","admin");			if ($con == false)			{				die("mysql connection failed<br />");			}			if (mysql_close($con) == false)			{				die("mysql connection did not close properly<br />");			}			mysql_select_db("coolgamer48_sql1",$con);			$sql = "CREATE TABLE person					(						UID int NOT NULL AUTO_INCREMENT,						PRIMARY KEY(UID),						FirstName varchar(15),						LastName varchar(15)					)";			mysql_query($sql,$con);			if (isset($_REQUEST[firstname]) == true && isset($_REQUEST[lastname]) == true)			{				$sql = "INSERT INTO person(FirstName, LastName) VALUES('$_REQUEST[firstname]','$_REQUEST[lastname]')";				mysql_query($sql,$con);			}		?>	</body><html>

I get these errors:Warning: mysql_select_db(): 1 is not a valid MySQL-Link resource in /home/www/alecbenzer.awardspace.com/mysql_test2.php on line 18Warning: mysql_query(): 1 is not a valid MySQL-Link resource in /home/www/alecbenzer.awardspace.com/mysql_test2.php on line 26Anyone know what these two mean?

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