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Math.log() returns the natural log. You can use the base change law to get a log in base 10. E.g.

20 * Math.log(0.5) / Math.log(10)

function log(n, base) {	return Math.log(n) / Math.log(base);}

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:) Ooh, the time I typed that, Synook took my place !!! Search a bit further, Suganya !First, I thought: humm, if I can't do it in JS, let's try in php:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><title>Untitled 1</title></head><body><?php$x = log(.5,10);$y = 20*$x;print $y;?></body></html>

Then I thought again: why doesn't it work in JS ?The answer is that JS uses natural log, meaning base e.So, you can still do it, more complicated, but it works :

<html><body><script type="text/javascript">var x = Math.log(.5)/Math.log(10);var y = 20*x;document.write("<br />" + y); </script></body></html>

Use the try-it editor to check it out: -- link to the log examples --

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