Regular Experssion For "text\text"

[DaNuGai]

I am looking for a regular expression for "Domain\UserName"...so essentially string "Text1\Text2" should return as valid. Minor condition is "text1" should have a max length of 8.Thanks.

[boen_robot]

[A-Za-z0-9-_]{1,8}\\[A-Za-z0-9-_]+

This says

one to eighth alphanumeric characters or a "-" or "_", followed by a "\", followed by one or more alphanumeric characters or a "-" or "_"

If it doesn't work (as I'm a little uncertain about the "-" and "_"), try this as well:

([A-Za-z0-9]|\-|\_){1,8}\\([A-Za-z0-9]|\-|\_)+

Just curious, we are talking about NetBIOS domain names, right?

[DaNuGai]

Thanks for your reply. By the way, the regular expression you gave me doesn't seem to work properly.If the first string is longer than 8 characters, it still returns true.Also, I am only want to use alpha characters (no Numberic and no Special characters). I tried something like

([A-Za-z]){1,8}\\([A-Za-z])+

and it doesnt' work as well.Thanks again for your help. I appreciate it.

[A-Za-z0-9-_]{1,8}\\[A-Za-z0-9-_]+

This saysIf it doesn't work (as I'm a little uncertain about the "-" and "_"), try this as well:

([A-Za-z0-9]|\-|\_){1,8}\\([A-Za-z0-9]|\-|\_)+

Just curious, we are talking about NetBIOS domain names, right?

[boen_robot]

Considering the fact we're talking about JavaScript, I have to ask... are you sure you've written the string correctly? You need to also escape the "\" in it, like so:

var regex = /^[A-Za-z]{1,8}\\[A-Za-z]+$/;var valString1 = "this\\valid";var valString2 = "domain\\thisIsAVeryLongUserName";var valString3 = "d\\t";var invString1 = "thisCouldBeValidIfOnlyMoreThanEighthCharactersWereAllowed\\thisToo";var invString2 = "domain\\\\ThisWasGoingToBeValidIfTwoSlashesWereAcceptable";var invString3 = "\\ThisWasGoingToBeValidIfTheDomainCouldBeEmpty";var invString4 = "domain\\";//Despite being a valid NetBIOS name, as per your request, the below is not acceptedvar invString5 = "my-server\\user";//both should be truealert(regex.test(valString1));alert(regex.test(valString2));alert(regex.test(valString3));//all three should be falsealert(regex.test(invString1));alert(regex.test(invString2));alert(regex.test(invString3));alert(regex.test(invString4));alert(regex.test(invString5));

[DaNuGai]

Thanks for your quick reply.I don't mean to be a pain but I am using the following site to test out the regular expressions and I am not getting the same results.Regular Expression Validator

[justsomeguy]

Those regex aren't running in Javascript, he's probably using VB for that. That might be the difference.

[DaNuGai]

That's what I thought too but I am getting the same results on the following website as well...Validator

[justsomeguy]

It's missing the start and end.^([A-Za-z]){1,8}\\([A-Za-z])+$^ means to match from the start of the string, and $ means to match until the end. The reason it was matching without that is because when you had a string like this:askldfjklasdjfklasjdf/askldfjdit was matching only this part:fklasjdf/askldfjdWith the start and end there, it means that it needs to match the entire string, not just part of it.

[DaNuGai]

Thank you so much JustSomeGuy I appreciate your help.

[justsomeguy]

Hey no problem. If you check post 4 you'll see that boen_robot wrote the same pattern in his test script, with the start and end.