[resolved] get text without the <p> </p>

[rvdokkum]

when using <xsl:value-of select="audio-caption"/>how do i get the text without the <p> </p>adding /p did not work : <xsl:value-of select="audio-caption/p"/>example of similar full xml file : http://staff.tumblr.com/api/readpart of my xml:

<?xml version="1.0" encoding="UTF-8"?>......<post><audio-caption><p>Test audio post of a ringtone.</p></audio-caption>

part of my xsl:

<?xml version="1.0" encoding="UTF-8"?><xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"><xsl:template match="/"> <h2>Blog</h2>	<table> 	  <xsl:for-each select="tumblr/posts/post">	  <tr>		<td>		  <xsl:choose>			<xsl:when test="@type='audio'">			 <xsl:element name="a"><xsl:attribute name="href"><xsl:value-of select="@url"/>			 </xsl:attribute>			   <xsl:value-of select="audio-caption"/>			 </xsl:element>

[Martin Honnen]

Frankly xsl: value-of should never give you markup, unless it is contained in the node in escaped form (e.g.

<audio-caption><![CDATA[<p>Test audio post of a ringtone.</p>]]></audio-caption>

).So I am currently not sure which problem you face, unless the input is different from what you posted. Please clarify. You might also want to mention which XSLT version (1.0 or 2.0) you use, that helps anyone trying to answer your posts to show you the right approach.

[rvdokkum]

Frankly xsl: value-of should never give you markup, unless it is contained in the node in escaped form (e.g.

<audio-caption><![CDATA[<p>Test audio post of a ringtone.</p>]]></audio-caption>

).So I am currently not sure which problem you face, unless the input is different from what you posted. Please clarify. You might also want to mention which XSLT version (1.0 or 2.0) you use, that helps anyone trying to answer your posts to show you the right approach.

thanks for the info.i added the required info to original post.there is nothing that can be done about the xml data. thats how tumblr generates it.

[rvdokkum]

thanks for the info.i added the required info to original post.there is nothing that can be done about the xml data. thats how tumblr generates it.

if i change the versions of xml and xsl to 2.0 then i can use the replace function to delete the <p> an </p>fn:replace(string,pattern,replace) - http://www.w3schools.com/Xpath/xpath_functions.aspwill the latest browsers on mac and windows support xml xsl v2?

[rvdokkum]

if i change the versions of xml and xsl to 2.0 then i can use the replace function to delete the <p> an </p>fn:replace(string,pattern,replace) - http://www.w3schools.com/Xpath/xpath_functions.aspwill the latest browsers on mac and windows support xml xsl v2?

how do i use the replace function to delete <p> and </p> at the end of the variable $long_audio_caption?part of my xsl code:

<?xml version="1.0" encoding="UTF-8"?><xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"><xsl:template match="/"> <h2>Blog</h2>	<table> 	  <xsl:for-each select="tumblr/posts/post">	  <tr>		<td>		  <xsl:choose>			<xsl:when test="@type='audio'">			  <xsl:text>audio node</xsl:text>			  <xsl:variable name="long_audio_caption">			  <xsl:value-of select="audio-caption"/>			  </xsl:variable>			  <xsl:copy-of select="$long_audio_caption" />

for now i use this workaround : http://geekswithblogs.net/Erik/archive/200.../01/120915.aspx

[Martin Honnen]

So your elements do not contain "p" elements but rather text nodes with escaped HTML markup. In that case if you don't want to output the escaped markup you have to remove it with text processing, in XSLT 1.0 you indeed need to use named templates, with XSLT 2.0 you can use replace.