akienghie09 0 Posted February 9, 2012 Report Share Posted February 9, 2012 Hi! I have a code where I populate the drop down list base on one of the columns in my database. It already display but the value of the chosen list did not affect my mysql query. Now I wanted to ask how I can put the value of the list to my mysql query.This is my code: <?php// db connection$db = "mds_reports";[/indent]if($connect = mysql_connect("172.16.8.32", "mds_reports", "password")) $connect = mysql_select_db($db); else die("Unable to connect".mysql_error());$date_from = $_POST['dfrom'];$date_to = $_POST['dto'];?><html><head><title>Cancelled Orders </title></head><body> <h1>Cancelled Orders</h1> <form name="cancelled_orders" method="POST" action="cancelled_orders_index.php"> Date From: <input type="text" name="dfrom" id="dfrom"> To: <input type="text" name="dto" id="dto"><br /><br /> <?php $i = $_POST['name']; $result_query = mysql_query ("SELECT name FROM restaurant_master") or die (mysql_error()); echo "<select name='name' value=''>Restaurant Name</option>"; $i=1; while($nt=mysql_fetch_assoc($result_query)) { echo "<option selected value='$i' > $nt[name] </option>"."<BR>"; $i++; } echo "</select>"; ?> <input name="submit" type="submit" value="Go"> </form> <table> <table border="2" cellpadding="2" cellspacing="1" style='width:100%;'> <tr> <th>Restaurant Code</th> <th>Restaurant Name</th> <th>Order No</th> <th>Order Source</th> <th>Payment Type</th> <th>Net Total</th> <th>Gross Total</th> <th>Reason</th> </tr> <?php if(isset($_POST['submit'])){ echo "Date select from $date_from to $date_to"."</p>"; echo "Restaurant: $i"."</p>"; $sql = "Select restaurant_master.code, restaurant_master.name, mds_orders.OrderNo, mds_orders.OrderSourceText AS 'Order Source', mds_orders.PaymentTypeText AS 'Payment Type', mds_orders.NetTotal, mds_orders.GrossTotal, ReasonMaster.ReasonDescription AS 'Reason' FROM mds_orders INNER JOIN ReasonMaster ON mds_orders.ReasonFKID = ReasonMaster.PKID INNER JOIN restaurant_master ON mds_orders.RestaurantID = restaurant_master.pkid WHERE mds_orders.OrderDate BETWEEN '".$date_from." 00:00:00' AND '".$date_to." 23:59:59' AND mds_orders.RestaurantID LIKE '$i' AND mds_orders.StatusFKID = 3 ORDER BY restaurant_master.code"; echo $sql; $result = mysql_query($sql) or die("Error: ".mysql_error()); $num_rows = mysql_num_rows($result); $i = 0; if (mysql_num_rows($result) >0) { while ($row = mysql_fetch_array($result,MYSQL_ASSOC)){ $csv .= $row['code'].",". $row['name'].",". $row['OrderNo'].",". $row['Order Source'].",". $row['Payment Type'].",". $row['NetTotal'].",". $row['GrossTotal'].",". $row['Reason'].","."<br>"; ?> <tr> <td><?php echo $row['code'];?></td> <td><?php echo $row['name'];?></td> <td><?php echo $row['OrderNo'];?></td> <td><?php echo $row['Order Source'];?></td> <td><?php echo $row['Payment Type'];?></td> <td><?php echo $row['NetTotal'];?></td> <td><?php echo $row['GrossTotal'];?></td> <td><?php echo $row['Reason'];?></td> </tr> <?php }}} ?> </table><br /> <form name="export" method="POST" action="cancelled_orders_export.php"> <input type="hidden" name="cancel_dfrom" id="data" value="<?=$date_from?>"> <input type="hidden" name="cancel_dto" id="data" value="<?=$date_to?>"> <input type="hidden" name="cancel_name" id="data" value="<?=$name;?>"> <input type="submit" name="extract" value="Extract"> </form></body></html> Thanks and best regards. Quote Link to post Share on other sites
Ingolme 1,019 Posted February 9, 2012 Report Share Posted February 9, 2012 Values of dropdown lists are sent to PHP in the $_GET or $_POST arrays. You can then put their value into the query like any other variable. If something's not working, the first thing to do is check what value the $_GET or $_POST element has. Quote Link to post Share on other sites
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