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Html 5 question about forms and php check


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Greetings, I am trying to write a small page where the user selects how many users. I want to use a drop down list. I believe I have everything in place. However, I can not get the submit information into my php script. Any thoughts? HTML / PHP code

<?php$num=$_POST["num"];$errorif ($num < 1) $error="Invalid option";if ($num == 1) header('Location: driven1.html');if ($num == 2) header('Location: driven2.html');if ($num == 3) header('Location: driven3.html');else header('Location: driven4.html');?><!DOCTYPE HTML><html><head><link href="driven1.css" rel="stylesheet" type="text/css"/><title>Driven support request</title></head><body><?php echo $error ?><div class="body"><header class="header"><!--Accelera logo--><img src="AcceleraLogo.jpg" alt="Accelera Logo" /></header><div class="div1"><form method="get">  <fieldset class="user1">   <label>How many users?</label> <br />   <select name="num">	<option value="1">1</option>	<option value="2">2</option>	<option value="3">3</option>	<option value="4+">4+</option>   </select> <br />   <input type="submit" value="Submit" />  </fieldset></form></div></div></body></html>

Edited by Fuzzy
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It could be because you don't have a semicolon after $error. I would probably just consolidate it to this:

<?php$num=$_POST["num"];$error = '';if ($num < 1) {  $error = 'invalid option';} else {  header('Location: driven' . $num . '.html');};?>

You might also want to specify the action too. Since you are submitting the form to itself, you could do this:

<form method='get' action='<?php echo $_SERVER['SCRIPT_NAME'] ?>'>

http://php.net/manua...bles.server.php

Edited by thescientist
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It could be because you don't have a semicolon after $error. You might also want to specify the action too. Since you are submitting the form to itself, you could do this:
<form method='get' action='<?php echo $_SERVER['SCRIPT_NAME'] ?>'>

http://php.net/manua...bles.server.php

I've not touched PHP in a while. I was never really all that good at it. So what your saying is convert my php script to a function and just add that to in place of the script name? I read through the php page you posted. I believe in order for this to work I'd have to convert to a function? Would you mind expanding on this? Maybe I'm over complicating the subject.
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i think you must be, because i don't know where you are getting functions from. $_SERVER is a global array just like POST or GET, but it already has members. Using SCRIPT_NAME was just a fail safe I'm suggesting in case not including an action attribute was causing your problem, but it's most likely that you didn't have a semi-colon after $error.

Edited by thescientist
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i think you must be, because i don't know where you are getting functions from. $_SERVER is a global array just like POST or GET, but it already has members. Using SCRIPT_NAME was just a fail safe I'm suggesting in case not including an action attribute was causing your problem, but it's most likely that you didn't have a semi-colon after $error.
Actually, it still wasn't working. So what I did was turn my script into a function. I then added that function to the action piece. I need to create the 4 pages. However, I believe it is working. Function
function number($num){if ($num < 1){  $error="Invalid option";}  else{  header('Location: driven' + $num + '.html');}}

Update to Form

<form method="get" action='<?php echo $_SERVER['number($num)']>

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Actually, it still wasn't working. So what I did was turn my script into a function. I then added that function to the action piece. I need to create the 4 pages. However, I believe it is working. Function
function number($num){if ($num < 1){  $error="Invalid option";}  else{  header('Location: driven' + $num + '.html');}}

Update to Form

<form method="get" action='<?php echo $_SERVER['number($num)']>

Well maybe not. It doesn't seem to be submitting the number.
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Your form uses a get method and you are trying to get the data using the post global variable, use

$num = $_GET['num'];

instead of

$num = $_POST['num'];

or change your form method to POST

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Your form uses a get method and you are trying to get the data using the post global variable, use
$num = $_GET['num'];

instead of

$num = $_POST['num'];

or change your form method to POST

Believe it or not it's not posting. It's not doing anything with the information. I've validated both html and php. I created a much simpler version of the code. It's still not working. I'm going to post up in the php forums.
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Is there any case where the page doesn't redirect? It looks like the HTML is never actually printed.
It's not printing at all. It's very wierd. Here is a very simple version of what I am trying to accomplish. It won't even do what it's suppose to. index.html
<!DOCTYPE HTML><html><head><title>Test PHP page</title></head><body><form method="post" action=""><label>Name:</label><input type="text" name="name" required><label>Age:<lable><input type="number" name="age" required><input type="submit" value="Submit" name="submit"></form></body></html><?php echo $_REQUEST['name'] ?><br /> <?php echo $REQUST['age'] ?>

Edited by Fuzzy
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so you're file isn't called index.php? I think it should. also, this is wrong, there's no underscore and no E

<?php echo $REQUST['age'] ?>

anyway, when I made it a php page, I got it to work.

<!DOCTYPE HTML><html>  <head><title>Test PHP page</title></head>  <body>	<form method="post" action="">	  <label>Name:</label>	  <input type="text" name="name" required>	  <label>Age:</label>	  <input type="number" name="age" required>	  <input type="submit" value="Submit" name="submit">	</form>  </body></html> <?php echo $_REQUEST['name']; ?><br /><?php echo $_REQUEST['age']; ?>

Edited by thescientist
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And again, the lack of semicolons. Every statement in PHP must end in a semicolon. And just to emphasize what scientist said, your file should be named index.php not index.html, unless your server is specifically set up to parse html files as php.

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so you're file isn't called index.php? I think it should. also, this is wrong, there's no underscore and no E
<?php echo $REQUST['age'] ?>

anyway, when I made it a php page, I got it to work.

<!DOCTYPE HTML><html>  <head><title>Test PHP page</title></head>  <body>	<form method="post" action="">	  <label>Name:</label>	  <input type="text" name="name" required>	  <label>Age:</label>	  <input type="number" name="age" required>	  <input type="submit" value="Submit" name="submit">	</form>  </body></html> <?php echo $_REQUEST['name']; ?><br /><?php echo $_REQUEST['age']; ?>

Setting it index.php does not change the status. It's not displaying any information
<?php$Name = $_POST['name'];$Age = $_POST['age'];?><!DOCTYPE HTML><html><head><title>Test PHP page</title></head><body><form method="post" action="index.php"><label>Name:</label><input type="text" name="name" required><label>Age:<lable><input type="number" name="age" required><input type="submit" value="Submit" name="submit"></form></body></html><?php// Testing to see if the submit button is workingif (isset($_POST['submit'])){echo "You have hit submit";echo $Name;echo $Age;}?>

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