SandySynaptik Posted March 15, 2012 Share Posted March 15, 2012 I want to define http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js as $jquerylink in a variable, so that I can link them by just typing $jquerylink. Link to comment Share on other sites More sharing options...
birbal Posted March 15, 2012 Share Posted March 15, 2012 treat it as string$link="http://ajax.googleap...1/jquery.min.js" Link to comment Share on other sites More sharing options...
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