elexion Posted April 26, 2012 Share Posted April 26, 2012 hey guys, I'm having some difficulty with this post request... function submit_data(par1,par2,par3,par4,par5){var xmlhttp;if (window.XMLHttpRequest) { xmlhttp=new XMLHttpRequest(); }else { xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); }xmlhttp.onreadystatechange=function() { console.log('readyState is => ' + xmlhttp.readyState); if (xmlhttp.readyState==4 && xmlhttp.status==200){document.getElementById("span").innerHTML=xmlhttp.responseText;} }xmlhttp.open("POST", "submit_survey.php",true);xmlhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");xmlhttp.send("name="+par1+"lastname="+par2+"street="+par3+"zipcode="+par4+"hometown="+par5);} When I go through the process using the google chrome console, the network tab tells me that the file is never called for some weird reason the console log tells me this readyState is => 1test.php:42 readyState is => 4when I hover over the initiator tab it shows me the full URL of test.php and somehow there's a new parameter in front of par1 can anyone spot anything wrong? Link to comment Share on other sites More sharing options...
dsonesuk Posted April 26, 2012 Share Posted April 26, 2012 if more than one sent use & between themxmlhttp.send("name="+par1+"&lastname="+par2+"&street="+par3+"&zipcode="+par4+"&hometown="+par5); Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now