Trouble with uploading images

[beennn]

Here's what I have:

$target = "images/profile_pictures/";$target = $target . basename( $_FILES['fileBrowser']['name']);$pic=($_FILES['fileBrowser']);mysql_query("UPDATE `user_accounts` SET profile_picture=$pic WHERE email =$Email") ;  if(move_uploaded_file($_FILES['fileBrowser']['tmp_name'], $target))  {  echo "The file ". basename( $_FILES['uploadedfile']['fileBrowser']). " has been uploaded, and your information has been added to the directory";  }  else {   echo "Sorry, there was a problem uploading your file.";  }

However I get errors at:

$target = $target . basename( $_FILES['fileBrowser']['name']);

$pic=($_FILES['fileBrowser']);

if(move_uploaded_file($_FILES['fileBrowser']['tmp_name'], $target))

I found out how to do this originally at: http://php.about.com/od/phpwithmysql/ss/Upload_file_sql.htm If someone could give me a hint at what's wrong, id be greatful

[Don E]

For this: $target = $target . basename( $_FILES['fileBrowser']['name']); You can just have:

 $target = $target . $_FILES['fileBrowser']['name'];

This $pic=($_FILES['fileBrowser']);, you're probably wanting to do this:

$pic = $_FILES['fileBrowser']['name'];

Edited May 29, 2012 by Don E

[justsomeguy]

If you're getting an error every time you try to access the item in the $_FILES array then it probably doesn't exist. You can use print_r to print out the entire array to check it.