Jump to content

(Easy?) XML Merge


MMM
 Share

Recommended Posts

Hi, I'm new to XSLT and I got some problems with it. I want to merge 2 XML files. I want to copy everything from a main file and a specific element with its childs from a second file into the main root Element. Example: Main File:

<?xml version="1.0" encoding="utf-8"?><CAEXFile SchemaVersion="2.15" ...>	<InstanceHierarchy Name="Example">		...A lot of elements...	</InstanceHierarchy></CAEXFile>

2nd File:

<CAEXFile ...>		<SystemUnitClassLib Name="Function">	...A lot of elements...	</SystemUnitClassLib></CAEXFile>

Final File:

<?xml version="1.0" encoding="utf-8"?><CAEXFile SchemaVersion="2.15" ...>	<InstanceHierarchy Name="Example">		...A lot of elements...	</InstanceHierarchy>	<SystemUnitClassLib Name="Function">	...A lot of elements...	</SystemUnitClassLib></CAEXFile>

My try looks like this:

<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"><xsl:template match="CAEXFile"><xsl:copy>   <xsl:apply-templates select="@* | node()" /></xsl:copy></xsl:template> <xsl:template match="node() | @*"><xsl:copy-of select="." /></xsl:template> </xsl:stylesheet>

It copies the file correct, but how do I get the information out of the 2nd file? I tried something like this:

   <xsl:apply-templates	match="document('my2ndFile.xml')/SystemUnitClassLib/node()" />

but without success. I found some Topics which had the same issue, but it couldn't help me. I'd be very thankful for any help.

Link to comment
Share on other sites

Your XPath on the document() line is wrong... it should start with the file's root element, i.e. "CAEXFile". Try it like:

<xsl:template match="CAEXFile"><xsl:copy>   <xsl:apply-templates select="@* | node()" />   <xsl:apply-templates match="document('my2ndFile.xml')/CAEXFile/SystemUnitClassLib/node()" /></xsl:copy></xsl:template>

Link to comment
Share on other sites

Ahh ok, one mistake. But with a XSLT file like this:

<?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"><xsl:template match="CAEXFile"><xsl:copy>   <xsl:apply-templates select="@* | node()" />   <xsl:apply-templates match="document('my2ndFile.xml')/CAEXFile/SystemUnitClassLib/node()" /></xsl:copy></xsl:template> <xsl:template match="node() | @*"><xsl:copy-of select="." /></xsl:template> </xsl:stylesheet>

I receive the content of the main file doubled:

<?xml version="1.0" encoding="utf-8"?><CAEXFile SchemaVersion="2.15" ...>		<InstanceHierarchy Name="Example">				...A lot of elements...		</InstanceHierarchy>		<InstanceHierarchy Name="Example">				...A lot of elements...		</InstanceHierarchy></CAEXFile>

Link to comment
Share on other sites

Try it with a single apply-templates:

<xsl:template match="CAEXFile"><xsl:copy>   <xsl:apply-templates select="@* | node() | document('my2ndFile.xml')/CAEXFile/SystemUnitClassLib/node()" /></xsl:copy></xsl:template>

Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
 Share

×
×
  • Create New...