How to select every 2nd node in XSL

[dragoncat 0]

Below is an example of my code. The item tag loop through my code many times:

 

<item>

<title>Secret Court Palace Gardens</title>`enter code here`<link></link><description><p><a href=>aataka</a> has added a photo to the pool:</p><p><a href= title="Hampton Court Palace Gardens"><img src= width="240" height="107" alt="Secret Court Palace Gardens" /></a></p></description></item>

 

I need to select the url value in the 'img src' tag inside the 2nd 'a' tag. I tried something like below but didn't work. Can anyone help? Thanks very much.

 

<?xml version='1.0'?>

<xsl:stylesheet version="2.0" xmlns:xsl= xmlns:media=><xsl:output method="html" /><xsl:template match="/"><xsl:for-each select="rss/channel/item/description/p[2]/*"><img src="{a/@href}" style="margin:5px 5px" /></xsl:for-each></xsl:template></xsl:stylesheet>

[Martin Honnen 16]

Given the XML you have the "a" elements are children of the "p" elements so you would need to use

 

<xsl:for-each select="rss/channel/item/description/p[2]"><img src="{a/@href}" style="margin:5px 5px" /></xsl:for-each>

[dragoncat 0]

Hi Martin. Thanks a lot. I think that should work!