rootKID Posted September 3, 2013 Share Posted September 3, 2013 Okay, this is a little hard to explain, but i try. As you see on the attached/uploaded picture, i wish to make a div like the page i found some days ago, it's easy i know.. BUT, here comes my problem. I am using a template/global design via a file called template.php inside (root/templates/template.php), and in there i have my menu to be shown... now, i wish this sub-menu to be shown, and i have done that, only problem is, that file is to be used on global design, meaning this div will be shown on ALL files (pages). Now my question, is it possible with if and else statements (possible functions also), to make it show only on 1 file, the file called: webshop.php this is how my code inside template.php looks like right now: //=======MENU$HTMLOUT .= "<div id='menu'>"; $HTMLOUT .= "<a href='#'>123</a>"; $HTMLOUT .= "";$HTMLOUT .= "</div>";//=====SUB$HTMLOUT .= "<div id='under_menu'>"; $HTMLOUT .= "123";$HTMLOUT .= "</div>";//=====SUB//=======MENU my first thought was to use a if isset statement saying if a file was open, i did try search on google and other few forums/places, but without luck.. any ideas would be awsome! Link to comment Share on other sites More sharing options...
Mudsaf Posted September 3, 2013 Share Posted September 3, 2013 Have you tried this <?php$currentFile = $_SERVER["PHP_SELF"];$parts = Explode('/', $currentFile);$currentpage = $parts[count($parts) - 1];if ($currentpage == "webshop.php") {//Display script here}?> Link to comment Share on other sites More sharing options...
rootKID Posted September 3, 2013 Author Share Posted September 3, 2013 nope, but it works.. thanks! Link to comment Share on other sites More sharing options...
Mudsaf Posted September 6, 2013 Share Posted September 6, 2013 Np "stewie", let my death be quick and painless when you're ruling the world! Link to comment Share on other sites More sharing options...
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