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this script keep returning warning mysqli_num_rows expect paramter 1 to be a result boolean given. Why?

 

<html>
<body>
<h1>search engine</h1>
<form action="search.php" method="get">
<input type="text" name="k" size='50' />
<input type="submit" name="submit" value='Search' />
</form>
<hr />
<?php
include "connect.php";
$k = $_GET['k'];
$terms = explode(".", $k);
$query = "SELECT * FROM users WHERE ";
foreach($terms as $each) {
$i++;
if($i == 1) {
$query .= "keywords LIKE '%$each%' ";
} else {
$query .= "OR keywords LIKE '%$each%' ";
}
}
$query = mysqli_query($con, $query);
$numrows = mysqli_num_rows($query);
if($numrows > 0)
{
while($row = mysqli_fetch_array($query)) {
$id = $row['id'];
$title = $row['title'];
$description = $row['description'];
$keywords = $row['keywords'];
$link = $row['link'];
if($k == "") {
echo "";
} else {
echo "<h2><a href='$link'>$title</a></h2>
$description";
}
}
}
else
{
echo "no result on $k";
}
?>
</body>
</html>

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        $query .= "OR keywords LIKE '%$each%' ";    }}   $query = mysqli_query($con, $query);$numrows = mysqli_num_rows($query);

I think you should do it like this

        $query .= "OR keywords LIKE '%$each%' ";    }}   $result = mysqli_query($con, $query);$numrows = mysqli_num_rows($result);
Edited by Mudsaf

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The message means that your query failed. To find out why it failed, use the mysqli_error() function.

 

You've forgotten to initialize $i to a value before your first loop, which might also be causing the problem.

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