whats wrong?

[etsted]

this is a uploader script. in my phpmyadmin the image is stored in a type = blob.

it works, the image is being uploaded to phpmyadmin, but i still get an error.

 

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1

 

<?phpinclude "conn.php";$name = mysqli_real_escape_string($con, $_POST['name']);$details = mysqli_real_escape_string($con, $_POST['details']);$photo = addslashes(file_get_contents($_FILES['photo']['tmp_name']));$image = getimagesize($_FILES['photo']['tmp_name']);$imagetype = $image['mime'];echo "<br/>";$q = mysqli_query($con, "INSERT INTO animal VALUES('','$name','$details','$photo','$imagetype')") or die(mysqli_error($con));$r = mysqli_query($con, $q);if($r){ echo "information stored";}else{ echo mysqli_error($con);}?>

[thescientist]

because you execute the query twice, but the second time you pass a result object instead of a query as the second paramter.

$q = mysqli_query($con, "INSERT INTO animal VALUES('','$name','$details','$photo','$imagetype')") or die(mysqli_error($con));$r = mysqli_query($con, $q);