bigjim

You are using fgets with a filename. fgets uses a file handle resource from fopen, not a filename. If you are using PHP greater then 4.3, then you can use file_get_contents to get the entire contents of a file in a string, and you can use the filename with that:http://www.php.net/manual/en/function.file-get-contents.phpThat would return the entire contents in a string. If you want to split that up into lines, then use the explode function and split it on \n. The result will be an array of the lines in the file.

I am a student in a Linux class. I need to be able to search for lines within a file for certain text. The script I have written runs but delivers an empty array. I know the /etc/crontab file has the word "test" but I can't seem to get this to work properly. This is not my finished work, I just need to get the preg_grep function working before I can go any further.SCRIPT#! /usr/bin/php<?php fwrite(STDOUT, "Enter the name of the file you wish to open \n");$file = array(trim(fgets(STDIN)));$grepfile = preg_grep ( "/test/" , $file );print_r($grepfile);?>OUTPUTbigjim3@bigjim3-desktop:~$ ./assign4.phpEnter the name of the file you wish to open /etc/crontabArray()bigjim3@bigjim3-desktop:~$ Thoughts, Suggestions, Hints?TIA