Jeevan25

Whenever display_footer() is called, the script is terminated because it contains a exit() command at the end. Therefore I don't have to manually do anything else. I tried removing the form vars, but still no luck. I still have no clue why. Two different tables, and nothing in common except the id.Ohh quick edit:Nevermind. Thanks for you help. Just posting that reminded me that in both functions display_footer terminates script so thanks.

I have two functions. One is delete_part($part_id) which deletes a video clip with the passed id from mysql db. The other one is delete_report($part_id). This one deletes a report with the given id from the mysql db. Both $part_id are same. Here are the functions.

function delete_part($part_id) {	global $link, $page_name, $_GET;	if ($part_id < 1) {		display_header();		echo ("Error");		display_footer();	}		display_header();		$sql = 'DELETE FROM parts WHERE part_id = ' . $part_id;	$result = mysql_query($sql,$link);	if ($result)	{		echo ("<br /><br /><b>Successfully deleted</b>");	}	else		echo ("Error: " . mysql_error());			display_footer();}

function delete_report ($part_id) {	global $link,$db,$_GET,$_POST,$page_name;	display_header();		if ($part_id < 1) {		echo ("Invalid report!");		display_footer();	}		$sql = "DELETE FROM report WHERE report_part = " . $part_id;	$result = mysql_query($sql,$link);		if (!result) {		echo ("Error with deleting report: " . mysql_error());		display_footer();	}	else		$result;			echo ("Report successfully deleted.");		display_footer();}

Both work fine when called separately. But when I call them at the same time, the first function to be called work but the second one doesn't work. I tried placing both in different orders but only first one works. Anyone know why?

this is a javascript code:

<script language="JavaScript" type="text/javascript">var i,y,x="ab";y='';for(i=0;i<x.length;i+=2){y=y + unescape('%'+x.substr(i,2));}document.write(y);</script>

i believe that would output «.now when i browse the source code via a browser, i don't see the string but rather the hexadecimal code. i want to see the actual converted string that is stored in variable y. how do i do this? i dont know anything about javascript. pls help and thanks. ps: a challange from friend and wouldn't tell me the answer.