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Posts posted by darbok
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On 5/11/2017 at 9:15 PM, niche said:
The answer to your specific question is you'd use a $_GET or $_POST method.
I think i explained myself wrong possibly. I understand about submitting to mysql from php... but from what iv'e seen you need to list all the columns in the sql tables that the info has to go in from the php form. I was wondering if there was some way to do this without having to list all 30 fields that the php/sql connect statement has to post to individual.
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I was wondering when one has a php form with like 30 entries how does one organize or manage such a large list of entries to pass to mysql?
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I feel stupid, I can't figure out why i kept getting the error message "is currently unable to handle this request."
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<?php$con = mysqli_connect("localhost","mark","library","markdb");// Check connectionif (mysqli_connect_errno()){echo "Failed to connect to MySQL: " . mysqli_connect_error();}$sql = "INSERT INTO UserNames (FirstName, LastName)VALUES ('John', 'Doe')";if ($conn->query($sql) === TRUE) {echo "New record created successfully";} else {echo "Error: " . $sql . "<br>" . $conn->error;}$conn->close();?>i have my table set to varchar (16)
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is there a way to make a singular login for a wordpress website that also logs a person into the forums and the wiki at the same time?
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Looking at how form items are put into a mysql table, the part that seems daunting is if ones form has like 50 items... having to list all those IDs with their variables makes me wonder if there is a better way or if its just " it up buttercup.".
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A page break is only a concept in printed documents. You can use CSS page-break-after You'll need to wrap the phone numbers in an HTML element and apply the CSS rule to that.
I ment linebreak not pagebreak.
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how can i put a pagebreak between these?echo $phone = 3152245368;echo $phone = 3156045555;
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"request" is not an HTTP method. GET appends data to the URL and has a size limit, POST does not put the data in the URL and can send about as much data as the server will allow.
As far as the database is concerned, it doesn't really matter how the data got there.
GET requests are usually used for reading data without changing anything on the server while POST is used to give data to the server, so for a database-driven application the most common approach is to use POST to put the data in and GET to pull the data out.
Thank you!
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what is the best method for getting data from a form to a mysql DB? Post? get? request?
thanks
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I'm getting a resource #4 error, not sure how to fix it, but i bet its an easy fix that i'm not seeing.
<?php$result=mysql_query("SELECT * FROM topdata a, venuetop b, stats c, mid_data d, influence e, botdata f, accounts g WHERE (a.char_name=b.char_name) AND (b.char_name=c.char_name) AND (c.char_name=d.char_name) AND (d.char_name=e.char_name) AND (e.char_name=f.char_name) AND (f.char_name=g.log_name) AND (a.char_name="$_POST[char_name]")")or die ("Couldn't get character data.<br>".mysql_error()."<br>Please contact Savvannis with your login name, character name, the above error and the page address above.");$row=mysql_fetch_array($result);echo $result;?> -
thanks for the help, much appreciated, the hints and such were a good deal. To make it work I turned it into two files, one for the form and one for the php, I also changed the SQL column names to be one word all lower case instead of two words uppercase. I also took the single quote marks out of my column names.
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this is the error I get now. Parse error: syntax error, unexpected ';' in C:xampphtdocspracticeformspracticeforms.php on line 24 though i think it's gotten better.
<!doctype html>
<html><head><link rel="stylesheet" href="style.css"><meta charset="utf-8"><title> My Practice Page </title></head><body><?php$first_name = $_POST["firstname"];$last_name = $_POST["lastname"];$city = $_POST["city"];$db = MYSQLI_CONNECT('localhost','root','','practiceforms');if (!$db) {die("Connection failed: " . mysqli_connect_error());}echo 'Connected successfully';if(isset($_POST['first_name']) && isset($_POST['last_name']) &&(isset($_POST['city']));{$sql = "INSERT INTO users ('FIRST NAME', 'LAST NAME', 'CITY') VALUES('$first_name','$last_name','$city')";}mysqli_query($db, $sql);mysqli_close($db);?><form method="post" action="">First Name:<br><input type="text" name="firstname" value=""> <br>Last Name:<br><input type="text" name="lastname" value =""><br>City:<br><input type ="text" name="city" value=""> <br><input type="submit" name="submit" value="submit"></form></body></html> -
I see I think. I guess I was just trying to make a simple form to practice doing the basics of putting something into a table.
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yes I do.
I get this error.
Notice: Undefined index: first name in C:xampphtdocspracticeformspracticeforms.php on line 11Notice: Undefined index: last name in C:xampphtdocspracticeformspracticeforms.php on line 12Notice: Undefined index: city in C:xampphtdocspracticeformspracticeforms.php on line 13
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So, I've revised the code to this, I get no more error messages, but my input is still not going into the table.
<!doctype html><html><head><link rel="stylesheet" href="style.css"><meta charset="utf-8"><title> My Practice Page </title></head><body><?php$first_name = $_POST['first name'];$last_name = $_POST['last name'];$city = $_POST['city'];$db = MYSQLI_CONNECT('localhost','root','','practiceforms');if (!$db) {die("Connection failed: " . mysqli_connect_error());}$sql = "INSERT INTO users (first name, last name, city) VALUES ('$first_name','$last_name','$city')";mysqli_query($db, $sql);mysqli_close($db);?><form method="post" action="">First Name:<br><input type="text" name="First Name" value=""> <br>Last Name:<br><input type="text" name="Last Name" value =""><br>City:<br><input type ="text" name="city" value=""> <br><input type="submit" name="submit" value="submit"></body></html> -
hmm, ok... so then the info that is entered into the form, how then does it get connected to the variables like $first_name, $last_name, $city ?
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<!doctype html><html><head><link rel="stylesheet" href="style.css"><meta charset="utf-8"><title> My Practice Page </title></head><body><?$first_name = '';$last_name ='';$city ='';?>$db = MYSQLI_CONNECT('localhost','root','','practiceforms');$sql = "INSERT INTO users (first name, last name, city) VALUES('$first_name', '$last_name', '$city')";mysqli_query($db, $sql);mysqli_close($db);echo '<p> User added. </p>';<form method="post" action="">First Name: <input type="text" name="First Name" value="<?php $first_name;?>" <br>Last Name: <input type="text" name="Last Name" value ="<?php $last_name;?>"<br>City: <input type ="text" name="city" value=<?php $city; ?>" <br><input type="submit" name="submit" value="submit"></body></html>
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So i'm studying javascript, learning the different parts etc... but none of the training shows how to use it in a practical way in a webpage, thus far its all been academic, is there anywhere that I see practical ways to use it? or get examples.
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thats what i was doing wrong, I wasn't accounting for "and" even though verbally i was saying greater than 1 and less than 4, i wasn't writing the 'and' in... thanks.
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var numapples = 0;if (numapples >= 4) {document.write("I'm apple rich!");}else if (numapples > 1 < 4) { <------- this is the part i'm unsure of, how to make sometthing more then one number but less then another.document.write("I have some apples");}else {document.write("I'm apple poor!");}
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If i had say a paragraph of text on top of a paragraph of text, and then all the way to the right I wanted a side bar, i get the idea of making two paragraphs or photos to sit next to each other, but not how to get something like a sidebar all the way to the end.. could someone help me with this?
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I figured out how to use display: inline-block i'm sort of proud of myself for this... so my question is.... would i use containers if i had four paragraphs and i wanted two on top and two below in a grid sort of look?
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grid and me
in CSS
hmm alright, I'll need to investigate the uses and difference of float and block i guess.
php form and mysql
in PHP
Posted
So it's best to just it up and list all the fields?