jumbo125

Hy, I tried to read filenames of zip file. I use the jszip libaray to see the fileneams and check name and type, BUT the libaray can't show me the size of files. or i don't know how i can see it.

Does anybody knows a zip libary, which is easy to use? i don't want compress and uncompress, only read the files and their properties.....

thank you

No, normale i would Write Print_r($_FILES) and Show what the php file gives out. That is the reason, for my last question. I didn't know how i can see the Output when the Site doesn't change

Thank you for answer. I know how i get upload files via php like:$_FILES [inpuzname]But i Never Try to get files which are uploaded with jsThe other Problem is, that i Write with this file some Database entrys....It will be really nice to See some errorsI will Try the error massage postsSorry for my wr

But i Need diffrent namensMaybe i don't understand formdata. I think i need help again.I want to use $_FILES[input name] after upload.....The formdata have only one filename Parameter:Formdata(filename, file)How can i put the input files with the input Name in the formdata. Maybe i understand this, when i can see a code example.Than for your help

 

 

// Edit: i try it with an multiple array,

formData("name", "array");

array(

[0] => array

[0] => inputname e.g. field_1

[1] => array mit filename

[0] => filnema 1

[1] => filname2

[1] => array

[0] => inputname e.g. field_2

[1] => array with filenames from second input type

[0] => filename1

[1] => filename2

)

client.send(formData);

If this work, i have only ONE Problem.

i don_t can see the result, because it doesn't change to the php file.... omg, what can I do....

I click on "send" and get only one sentence in the console, but i don't know if there is an fail in the php file, or something more. what can i do to change the site???

i want to get out the POST files eand more.

I think it's reallay difficult to understand my Problem.

with the normall send method, without js submit buttons and action location i changed the site.

than i saw the files with echo and print_ and can create the perfect php file. Now i don't know, what i should wirte in the php file.

I know the method appendI don't understand how i can send the formDataFor exampleFormData1.append("file1","filelist1")FormData2.append ("file2", "filelist2")And more... Maybe 10 and more...But how i can send alltogether Client.send(formdata1,formdata3)

Thank you very michNow i know how i can put the multiple files in the var file.But i don't know how i use the other input tags. I put the var file in the formdata and send it with the Client.How can i send the other input tags? Can i create more formdata and send all formdata with one client

I try to create an Upload with javascript nad progress bar.

i found this code in the internet, but i can't change the code for my idea.

This is the script sample:

var client = null; function uploadFile(){ //Wieder unser File Objekt var file = document.getElementById("fileA").files[0]; var formData = new FormData(); client = new XMLHttpRequest(); if(!file) return; formData.append("datei", file); client.onerror = function(e) { alert("onError"); }; client.open("POST", "upload.php"); client.send(formData);}

my first problem is, that the autor used ONE input tag an set no MULTIPLE.

I have a multiple input tag. I think it's enoug to change:

var file = document.getElementById("fileA").files[0];

to

var file1 = document.getElementById("file1").files; //dlete [0] for all files

and

formData.append("datei", file);

to

formData.append("file1[]", file);// add [] to create an array

is this correct?

AND MY IMPORTANT PROBLEM is, that i have more input tags:

<form>

<input type="file" name="file1">

<input type="file" name="file2">

<input type="file" name="file3">

</form>

How can i pass the code for mulitple tags with different names???????

I search since 4 days for an idea. It will be perfect, if i can send all input with ONE clinet.

IT's really important to read the files with $_FILES[file1], $_FILES[file2]