please i need help
I created a php upload function to upload some photos to the database. Created a form
<form action="upload.php" enctype="multipart/form-data" method="POST">
<input class="pl-2 input" type="file" name="image" id="image"><br>
<input class="send" type="submit" value="upload picture" name="upload">
</form>
and in another file called upload.php
<?php
if (isset($_POST['upload'])){
$filename=$_FILES['image']['name'];
$tempname=$_FILES['image']['tmp_name'];
$filesize=$_FILES['image']['size'];
$filetype=$_FILES['image']['type'];
$folder="images/" . $filename;
$conn=mysqli_connect("localhost","root","","mojeslike");
mysqli_query($conn,"INSERT INTO photos(image) VALUES ('{$filename}')");
if(move_uploaded_file($tempname,$folder)){
echo "image uploaded successfully";
}else{
echo "failed to upload";
}
}
?>
in a body tag
<section class="container first">
<h1>PICTURE GALLERY</h1>
there is also a css file with styling, which is why this clearfix was included
means, in one div tag I have an image and a bootstap modal. Another image is always displayed, and when I click on the button below the image, I would like them to show me data about the image. if I put echo $filesize and echo $filetype in the body of the modal, I get data about the last upload picture. I want to always have another data, each picture to display its own data, but I don't know that, so please help me with this problem. Thank you.
different data in the modal
in PHP
Posted · Edited by Klarez
Hi ,
please i need help
I created a php upload function to upload some photos to the database. Created a form
<form action="upload.php" enctype="multipart/form-data" method="POST">
<input class="pl-2 input" type="file" name="image" id="image"><br>
<input class="send" type="submit" value="upload picture" name="upload">
</form>
and in another file called upload.php
<?php
if (isset($_POST['upload'])){
$filename=$_FILES['image']['name'];
$tempname=$_FILES['image']['tmp_name'];
$filesize=$_FILES['image']['size'];
$filetype=$_FILES['image']['type'];
$folder="images/" . $filename;
$conn=mysqli_connect("localhost","root","","mojeslike");
mysqli_query($conn,"INSERT INTO photos(image) VALUES ('{$filename}')");
if(move_uploaded_file($tempname,$folder)){
echo "image uploaded successfully";
}else{
echo "failed to upload";
}
}
?>
in a body tag
<section class="container first">
<h1>PICTURE GALLERY</h1>
<article>
<?php
$rez=mysqli_query($conn,"SELECT * FROM photos");
while($row=mysqli_fetch_array($rez)){
?>
<div class="photo">
<img src="<?php echo $row['image']; ?>" >
<div>
<!-- Button to Open the Modal -->
<button type="button" class="btn btn-primary" data-toggle="modal" data-target="#myModal">
<h4>about picture</h4>
</button>
<!-- The Modal -->
<div class="modal fade" id="myModal">
<div class="modal-dialog modal-sm">
<div class="modal-content">
<!-- Modal Header -->
<div class="modal-header">
<h4 class="modal-title">Image details</h4>
<button type="button" class="close" data-dismiss="modal">×</button>
</div>
<!-- Modal body -->
<!-- Modal footer -->
<div class="modal-footer">
<button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>
</div>
</div>
</div>
</div>
</div>
</div>
<?php
}
?>
</article>
<div class="clearfix"></div>
</section>
there is also a css file with styling, which is why this clearfix was included
means, in one div tag I have an image and a bootstap modal. Another image is always displayed, and when I click on the button below the image, I would like them to show me data about the image. if I put echo $filesize and echo $filetype in the body of the modal, I get data about the last upload picture. I want to always have another data, each picture to display its own data, but I don't know that, so please help me with this problem. Thank you.