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lucasjay

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Posts posted by lucasjay

  1. In this case, specifically, because it's for a university assignment, and the requirement that's getting me is as follows:"Salesreps have an ID code of which the last four characters give their delivery_id". So while I could select them and get that result, I didn't want to write any queries and instead just have the answer on the table. Maybe you're right though, I guess I could just create a view that combines the two columns into a new one. Still, it truly baffles me that want I was trying to achieve isn't possible at all...

  2. Ok, well I gave that a go - here is my trigger:

    CREATE TRIGGER salesrep_id_create for insert ON salesrepsFOR EACH ROW	 set new.salesrep_id = concat(new.srid,new.delivery_id);

    Where salesreps is the table, srid is an auto-incremented column, and delivery_id is a foreign key. Unfortunately this doesn't work because srid is auto-incremented and doesn't have a value until after the row is inserted. I have tried all the various combinations with various errors as a result: Here I found someone who had the same problem: http://mysqldatabaseadministration.blogspot.com.au/2006/03/mysql-triggers-accessing-value-of-auto.html So I don't think this is going to work :( Thanks for the suggestion though. I don't really get composite primary keys... Why can't I just make a composite primary key out of srid and delivery_id and display a column that is sriddelivery_id which displays the actual values of the composite keys? It seems odd that they exist but you can't actually see them when you select * from table...

  3. I cant believe how little success I have had in discovering the answer to my problem on Google over the last hours of trawling... I have an ID number (salesrep_ID) that I want to use as the primary key, and I want it to be comprised of another field (delivery_id) and an auto increment number. i.e. delivery id = 1234 salesrep_id = 0011234 ....HOW? Oh god how? It seems the thing to do would be to create a new field that is autoincremented and then make salesrep_ID the composite primary key of the incremented field and delivery_id. But I want this to be displayed when I query "select * from salesreps" (salesreps is the table name): salesrep_ID0011234 NameJohn Smith Address123 Fake St delivery_id1234 This must be simple? I'm so confused :( My love and adoration for anyone who can help.

  4. index.html

     <html><head></head><body><script type="text/javascript"> xhttp=new XMLHttpRequest();  xhttp.open("GET","books.xml",false); xhttp.send(); xmlDoc=xhttp.responseXML;  x=xmlDoc.getElementsByTagName("title");  for (i=0;i<x.length;i++)   {   document.write(x[i].childNodes[0].nodeValue);   document.write("<br />");   }</script></body></html>

    books.xml:

    <?xml version="1.0" encoding="ISO-8859-1"?><!-- Edited by XMLSpy® --><bookstore><book category="cooking"><title lang="en">Everyday Italian</title><author>Giada De Laurentiis</author><year>2005</year><price>30.00</price></book><book category="children"><title lang="en">Harry Potter</title><author>J K. Rowling</author><year>2005</year><price>29.99</price></book><book category="web"><title lang="en">XQuery Kick Start</title><author>James McGovern</author><author>Per Bothner</author><author>Kurt Cagle</author><author>James Linn</author><author>Vaidyanathan Nagarajan</author><year>2003</year><price>49.99</price></book><book category="web" cover="paperback"><title lang="en">Learning XML</title><author>Erik T. Ray</author><year>2003</year><price>39.95</price></book></bookstore>

  5. It can't be the length property, as like i said I took away the for loop from the example just to test, and that's how I get opera to display an error, instead of nothing at all. The error is in this line: document.write(x[0].childNodes[0].nodeValue); in that for some reason the node from the xml file, which is simple text "cannot be converted to object". It works in the TryIt editor, and in Safari. I would try more browsers, but for my purposes I'm really mostly interested in Opera. Just to clarify, in the example, and in my code above, there is a simple xml file with some book information, and we want to display a list of all the books in the xml file, hence the for loop. But to test a simpler version, literally all I want to do, is get the title of the first book. So getElementsByTagName("title") gets the title tags, which we store in the variable x. Then the code document.write(x[0].childNodes[0].nodeValue); gets the first title tag (x[0]) then the text inside that tag (childNodes[0]) and returns the nodevalue, which should be the title of the first book in the xml file. x[0], to my understanding, should simply contain the text "title", but 'cannot be converted to object', which i just plain don't get. (Like I said, I'm a beginner). The code works fine in Safari, so theres obviously some element that is incompatible with opera, but I don't know of any alternative methods.

  6. Hi everybody,I've been working my first website, and I came to a section where I wanted to get data from an XML file and display it on the web page. So I followed the XML and XML DOM tutorials, but I've hit a maddening wall, thanks to Opera. ?script?xhttp=new XMLHttpRequest();xhttp.open("GET","books.xml",false);xhttp.send();xmlDoc=xhttp.responseXML;x=xmlDoc.getElementsByTagName("title"); for (i=0;i?x.length;i++) {="" document.write(x.childnodes[0].nodevalue);="" document.write("?x.length;i++);{ document.write(x.childNodes[0].nodeValue); document.write("?br /?");}?/script? This is the code taken straight from the tutorial, and I've saved "books.xml" from there just to check I wasn't making any of my own errors. It works fine in Safari and displays the book list, but nothing displays in Opera. It doesn't throw up any errors either, but when I swap the for loop in the code to the simpler document.write(x[0].childNodes[0].nodeValue); I get the error in the inspector: Uncaught exception: TypeError: Cannot convert 'x[0]' to object. I've done everything I could think of, but no luck, and I cannot fathom what the problem might be. Please help! Regards,Luke

  7. Hi everybody,I've been working my first website, and I came to a section where I wanted to get data from an XML file and display it on the web page. So I followed the XML and XML DOM tutorials, but I've hit a maddening wall, thanks to Opera. xhttp=new XMLHttpRequest(); xhttp.open("GET","books.xml",false); xhttp.send(); xmlDoc=xhttp.responseXML; x=xmlDoc.getElementsByTagName("title"); for (i=0;i

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